Math topic中文

Derivative as gradient

derivative of f(x)f(x) as the gradient of the tangent to the graph of y=f(x)y = f(x) at a point

Practice questions

  1. 1A curve has the equation y=2x−33x+4y = \frac{2x - 3}{3x + 4}, where x≠−43x \ne -\frac{4}{3}. The normal to the point PP on the cur…
  2. 2The normal to the curve y=2tan⁡3x−1y = 2\tan 3x - 1 at point P(π3,−1)P\left(\frac{\pi}{3}, -1\right) crosses the yy-axis at point AA…
  3. 3The point PP lies on the curve y=ln⁡(x+1x−1)y = \ln\left(\frac{x+1}{x-1}\right) for x>1x > 1. The normal to the curve at PP is par…
  4. 4The figure shows part of the curve y=g(x)y = g(x). (2,8)(2, 8) and (6,1)(6, 1) are two points on the curve. Given that ∫26y dx=32\int_{2}^{6} y \text{ } dx = 32…
  5. 5The diagram shows part of the curve y=3e−12x−6y = 3e^{-\frac{1}{2}x} - 6 which crosses the xx-axis at PP and the yy-axis at QQ…
  6. 6已知函数f(x)=x2−ax(a≠0)f(x)=x^{2}-ax(a\neq 0),g(x)=ln⁡xg(x)=\ln x,f(x)f(x)图象与xx轴异于原点的交点MM处的切线为l1l_{1},g(x−1)g(x-1)与xx轴的交点NN处的切线为…
  7. 7The diagram shows part of the curve y=3x+4y = \sqrt{3x + 4}. The line ABAB is tangent to the curve at AA. The points BB an…
  8. 8The gradient function of a curve y=f(x)y = f(x) is given by 36(2x+1)2\frac{36}{(2x+1)^2} for x>−12x > -\frac{1}{2}. The curve passes t…
  9. 9When the height of liquid in a container is hh m, the volume of liquid is V m3V\text{ m}^3 where V=0.06[(4h+1)3−7] and h≥0.25V = 0.06 \left[ (4h + 1)^3 - 7 \right] \text{ and } h \ge 0.25…
  10. 10曲线y=3x−2y=\sqrt{3x-2}在点(1,f(1))(1,f(1))处的切线方程为 A. x−2y+1=0x-2y+1=0 B. 3x−y−2=03x-y-2=0 C. 3x−2y−1=03x-2y-1=0 D. 3x+2y−5=03x+2y-5=0
  11. 11若曲线y=x−12y=x^{\mathrm{{-}}\frac{1}{2}}在点(a,a−12)(a,a^{\mathrm{{-}}\frac{1}{2}})处的切线与两个坐标轴围成的三角形的面积为1818,则aa的值为___.
  12. 12The diagram shows part of the curve y=(1−x)(x−4)y = (1 - x)(x - 4) and two lines l1l_1 and l2l_2. The lines l1l_1 and l2l_2 are ta…
  13. 13Given the curve y=12e2x−13e−3x+13y = \frac{1}{2}e^{2x} - \frac{1}{3}e^{-3x} + \frac{1}{3} and the normal to the curve at point P(ln⁡2,5524)P\left(\ln 2, \frac{55}{24}\right)…
  14. 14The diagram below shows the graph of y=12x+1y = \frac{1}{2x+1} and the tangent to the curve where the curve intersects the yy…
  15. 15The diagram shows part of the curve y=1(34x−5)2+1y = \frac{1}{\left(\frac{3}{4}x - 5\right)^2} + 1. PP is the point on the curve w…
  16. 16The point A lies on the curve y=xln⁡x2y = x \ln x^2, x>0x > 0. The tangent to the curve at A is parallel to the line y−3x=1y - 3x = 1…
  17. 17The diagram shows part of the curve y=sin⁡xy = \sin x. A is a point on the curve that lies on the line x=π3x = \frac{\pi}{3}. T…
  18. 18The diagram shows part of the curve y=4−e−2xy = 4 - e^{-2x} which crosses the axes at AA and at BB. Find the coordinates of…
  19. 19The diagram shows part of the curve y=ex−1−2y = e^{x-1} - 2. The point P(2, e−2)P(2,\ e-2) lies on the curve and the normal to the cu…
  20. 20The diagram shows part of the curve y=4x+5y = \sqrt{4x + 5}. The normal of the curve at PP meets the xx-axis at TT. The xx…
  21. 21A curve is such that d2ydx2=6e3x−x\frac{d^2y}{dx^2} = 6e^{3x} - x and passes through the point (2,23e6)\left(2, \frac{2}{3}e^6\right). Gi…
  22. 22The equation of a curve is y=5x6−2xy = \frac{5x}{6 - 2x}. Find the xx-coordinates of the points at which the gradient of the…
  23. 23The graph shows part of the curve y=−3(2x−4)−1/3y = -3(2x-4)^{-1/3}. The point P(−2, 1.5)P(-2,\ 1.5) lies on the curve and the normal to the…
  24. 24The diagram shows part of the curve y=2x+4y = \sqrt{2x + 4}, meeting the xx-axis at the point AA and the yy-axis at the p…
  25. 25The diagram shows part of the curve y=2sin⁡2x+1y = 2 \sin 2x + 1. PP is the maximum point of the curve and QQ is the point on t…
  26. 26若曲线y=e−xy=e^{-x}上点PP处的切线平行于直线2x+y+1=02x+y+1=0,则点PP的坐标为 ___ .
  27. 27Point PP lies on the curve y=kx22−xy = \frac{kx^2}{\sqrt{2-x}}, where kk is a constant. The xx-coordinate of PP is −2-2. G…
  28. 28The diagram shows part of the curve y=14x2−12ln⁡(x3)y = \frac{1}{4}x^2 - \frac{1}{2}\ln\left(\frac{x}{3}\right) and P(3, 2.25)P(3,\,2.25) is…
  29. 29The function is defined by g(x)=x2−4x2+6g(x) = \frac{x^2 - 4}{x^2 + 6}, x>0x > 0. Explain, with working, whether g(x)g(x) is an increa…
  30. 30The diagram shows part of the curve y=27+8(x−2)3y = 27 + \frac{8}{(x-2)^3} which crosses the axes at points AA and BB. Explain w…
  31. 31The diagram shows part of the curve y=2sin⁡x2y = 2\sin\frac{x}{2}, where AA lies on the curve. The xx-coordinate of AA is 4π3\frac{4\pi}{3}…
  32. 32设曲线f(x)=ax2f(x)=ax^{2}在点(2,4a)(2,4a)处的切线与直线4x−y+4=04x-y+4=0垂直,则a=()a=(\quad) A. 22 B. −116-\dfrac{1}{16} C. 12\dfrac{1}{2} D.…
  33. 33已知曲线y=∣x∣exy=\dfrac{|x|}{{{e}^{x}}}在x=−1x=-1处的切线和它在x=x0(x0>0)x={{x}_{0}}\left({x}_{0} > 0\right) 处的切线互相垂直,设x0∈(m4,m+14),m∈Z{{x}_{0}}\in (\dfrac{m}{4},\dfrac{m+1}{4}),m\in Z…
  34. 34The line 2y+x+a=02y + x + a = 0 is a normal to the curve y=2x2−3x+1y = 2x^2 - 3x + 1 at the point PP. Find the coordinates of PP. De…
  35. 35设函数f(x)=ax+bxf(x)=ax+ \dfrac {b}{x},曲线y=f(x)y=f(x)在点M(3,f(3))M( \sqrt {3},f( \sqrt {3}))处的切线方程为2x−3y+23=02x-3y+2 \sqrt {3}=0. ((Ⅰ))求f(x)f(x)…
  36. 36Answer ALL the questions The function ff is defined, for all values of xx, by f(x)=(2x−x2)exf(x) = (2x - x^2)e^x. Find the ran…
  37. 37The diagram shows part of the curve y=76x+1y = \frac{7}{6x + 1} intersecting the yy-axis at A(0,7)A(0, 7). The tangent to the cu…
  38. 38A curve is such that f′′(x)=6x−10\mathrm{f}''(x) = 6x - 10. The tangent to the curve y=f(x)y = \mathrm{f}(x) at the point (1,−2)(1, -2) pa…
  39. 39Find the set of values of xx for which the curve y=−x2+2x+4y = -x^2 + 2x + 4 lies below another curve y=x2−2x−2y = x^2 - 2x - 2 and re…
  40. 40设函数f(x)=ln⁡xf(x)=\ln x,g(x)=xx+1g(x)=\dfrac{x}{x+1},记F(x)=f(x)−g(x)(1)F(x)=f(x)-g(x)(1)求曲线y=f(x)y=f(x)在x=ex=e处的切线方程; (2)求函数F(x)F(x)在[1e,e2][\dfrac{1}{e},e^{2}]…
  41. 41设函数f(x)=xln⁡ x+2x3f(x)=x\ln\:x+2x^{3},则曲线y=f(x)y=f(x)在点(1,2)(1,2)处的切线方程是___.
  42. 42已知函数f(x)=axexf(x)= \dfrac {ax}{e^{x}}在x=0x=0处的切线方程为y=xy=x. (1)求aa的值; (2)若对任意的x∈(0,2)x∈(0,2),都有1f(x)>k+2x−x2 \dfrac {1}{f(x)} > k+2x-x^{2}…
  43. 43The equation of a curve is y=xe2xy = \frac{x}{e^{2x}}. Find an expression for dydx\frac{dy}{dx}. Given that xx is changing at…
  44. 44The diagram shows part of the graph of y=22+xy = 2\sqrt{2 + x}. It cuts the x-axis at (−2,0)(-2,0). The line y=2xy = 2x meets the…
  45. 45已知函数f(x)=mln⁡xf(x)=m\ln x. (1)讨论函数F(x)=f(x)+1x−1F(x)=f(x)+ \dfrac {1}{x}-1的单调性; (2)定义:“对于在区域DD上有定义的函数y=f(x)y=f(x)和y=g(x)y=g(x),若满足f(x)⩽g(x)f(x)\leqslant g(x)…
  46. 46Given that y=(x+2)x−1y = (x + 2)\sqrt{x - 1}, show that dydx=kx2x−1\frac{\text{d}y}{\text{d}x} = \frac{kx}{2\sqrt{x - 1}} where kk is co…
  47. 47For a particular curve d2ydx2=3x−2\frac{\text{d}^2 y}{\text{d}x^2} = 3x - 2. The tangent to the curve at the point A(4,−40)A(4, -40) is…
  48. 48已知函数f(x)=xsin⁡x+acos⁡x+xf(x)=x\sin x+a\cos x+x,a∈Ra∈R. ((Ⅰ))当a=−1a=-1时,求曲线y=f(x)y=f(x)在点(0,f(0))(0,f(0))处的切线方程; ((Ⅱ))当a=2a=2时,求f(x)f(x)…
  49. 49A curve has equation y=x2−x−12y = x^2 - x - 12. Points A and B lie on the curve and have x-coordinates of kk and 2k2k respecti…
  50. 50曲线y=2x+ln⁡xy=2x+\ln x在x=1x=1处的切线的倾斜角为αα,则cos⁡α+sin⁡α\cos α+\sin α的值为( ) A. 1010\dfrac{ \sqrt{10}}{10} B. 105\dfrac{ \sqrt{10}}{5}…
  51. 51The diagram shows part of the curve y=3x−2y = \sqrt{3x-2}. The normal to the curve at BB meets the xx-axis at CC. Given t…
  52. 52已知函数f(x)=ex(x2−2x+a)(f(x)=e^{x}(x^{2}-2x+a)(其中a∈Ra∈R,aa为常数,ee为自然对数的底数)). ((Ⅰ))讨论函数f(x)f(x)的单调性; ((Ⅱ))设曲线y=f(x)y=f(x)…
  53. 53A curve CC has equation y=1−1xy = 1 - \frac{1}{x}, where x≠0x \ne 0. The line ll is the tangent to CC at x=ax = a, where aa…
  54. 54过点P(2,−1)P(2,-1)作抛物线CC:x2=2yx^{2}=2y的两条切线,切点分别为AA,BB,则直线ABAB的方程为 ___.
  55. 55The diagram shows part of the curve y=2x+5y = \sqrt{2x+5}. A is a point on the curve and the x-coordinate of A is 2. The nor…
  56. 56The diagram shows part of the curve y=5+4e2xy = 5 + \frac{4}{e^{2x}} intersecting the yy-axis at point PP. The tangent to th…
  57. 57The diagram shows part of the curve of y=x(x−2)2y = x(x-2)^2, which passes through the point P(1,1)P(1, 1). Show that the equation…
  58. 58已知函数f(x)=ax2+xln⁡x+xf(x)=ax^{2}+x\ln x+x. (1)若a=1a=1,求函数f(x)f(x)在(1,f(1))(1,f(1))处的切线方程; (2)若a=−ea=-e,证明:方程∣f(x)∣−ln⁡x=12x|f(x)|-\ln x= \dfrac {1}{2}x…
  59. 59The equation of a curve is y=2x3+6x2−18x+5y = 2x^3 + 6x^2 - 18x + 5. Find the coordinates of the stationary points and determine the…
  60. 60过抛物线x2=4yx^{2}=4y在第一象限内的一点PP作切线,切线与两坐标轴围成的三角形的面积为12 \dfrac {1}{2},则点PP到抛物线焦点FF的距离为()() A. 11 B. 22 C.…