Math topic中文

Gradient two points

finding the gradient of a straight line given the coordinates of two points on it

Practice questions

  1. 1已知圆CC:(x+1)2+(y−1)2=1(x+1)^{2}+(y-1)^{2}=1与xx轴切于AA点,与yy轴切于BB点,设劣弧A^B \hat AB的中点为MM,则过点MM的圆CC的切线方程是()() A…
  2. 2已知过点P(1,32)P(1,\dfrac{3}{2})的曲线CC的方程为(x−1)2+y2+(x+1)2+y2=2a.(Ⅰ)\sqrt{{{(x-1)}^{2}}+{{y}^{2}}}+\sqrt{{{(x+1)}^{2}}+{{y}^{2}}}=2a.(Ⅰ)求曲线CC的标准…
  3. 3ABCD is a parallelogram. A is the point (−6,−2)(-6,-2) and B is the point (−4,−7)(-4,-7). BC→=(8−2)\overrightarrow{BC} = \begin{pmatrix}8\\-2\end{pmatrix}…
  4. 4圆x2+y2−2x−5=0x^{2}+y^{2}-2x-5=0和圆x2+y2+2x−4y−4=0x^{2}+y^{2}+2x-4y-4=0的交点为AA、BB,则线段ABAB的垂直平分线方程为()(\quad) A. x+y−1=0                           x+y-1=0\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: …
  5. 5Given that the coordinates of point A is (−2,11)(-2,11) and point B is (5,−11)(5,-11). Find length ABAB. Answer ... equation of th…
  6. 6K is the point (7,−8)(7, -8) and L is the point (x,y).\n\nThegradientofthelineKLis(x, y).\n\nThe gradient of the line KL is \frac{2}{3}.\n\nMaverickclaimsthatitispossibletoexpress.\n\nMaverick claims that it is possible to express …
  7. 7The points A(0,2) and B(1,0) lie on the graph y=x2+ax+by = x^2 + ax + b. Find the values of a and b. Answer a = ... b = ... C i…
  8. 8The diagram shows three points A(-16, 0), B(0, 12) and C(8, 2). A circle is drawn with centre C such that AB is a tangen…
  9. 9The triangle with vertices A (2, 5), B (−2, −3) and C (2, −2) is shown in the diagram below. Find (a) the area of triang…
  10. 10The diagram shows two congruent isosceles triangles, PQS and RSQ. PQ and RS are parallel to the x-axis. Write down the c…
  11. 11The diagram shows a trapezium in which ADAD is parallel to BCBC and angle ADC=ADC = angle BCD=90∘BCD = 90^\circ. The points BB…
  12. 12The variables x and y are connected by the equation y=2x+6x−7y = 2x + \dfrac{6}{x} - 7. Some corresponding values of x and y ar…
  13. 13若点P(1,1)P(1,1)为圆x2+y2−6x=0x^{2}+y^{2}-6x=0的弦MNMN的中点,则弦MNMN所在直线的方程为 ()(\quad) A. 2x+y−3=02x+y-3=0 B. x−2y+1=0x-2y+1=0 C. x+2y−3=0x+2y-3=0…
  14. 14若双曲线的中心为原点,F(0,−2)F(0,-2)是双曲线的焦点,过FF的直线ll与双曲线相交于MM,NN两点,且MNMN的中点为P(3,1)P(3,1),则双曲线的方程为()(\quad) A. x23−y2=1\dfrac{x^{2}}{3}-y^{2}=1…
  15. 15In the diagram, A is the point (−2,4)(-2, 4), and C is the point (4,7)(4, 7). AB is a vertical line. The line BC has gradient 32\frac{3}{2}…
  16. 16若A(-2,3)A(\text{-}2\text{,}3),B(3,-2)B(3\text{,-}2),C(1,m)C(1\text{,}m)三点共线,则mm的值为()() A. -2\text{-}2 B. -1\text{-}1 C.…
  17. 17Triangle ABC is equilateral. CAD and ABE are straight lines and AD = BE. Show that triangle ABD and triangle BCE are con…
  18. 18The point A is (0,7) and the point B is (6,9). Express AB→\overrightarrow{AB} as a column vector. The equation of AB is x…
  19. 19已知椭圆C:x23+y22=1C: \dfrac {x^{2}}{3}+ \dfrac {y^{2}}{2}=1上的动点PP与其顶点A(−3,0)A(- \sqrt {3},0),B(3,0)B( \sqrt {3},0)不重合. ((Ⅰ))求证…
  20. 20The coordinates of P and Q are (0, 3) and (15, 12) respectively. Find the equation of PQ. Find the perimeter of trapeziu…
  21. 21已知椭圆x23+y24=1\dfrac{x^{2}}{3}+\dfrac{y^{2}}{4}=1的弦被点(1,1)(1,1)平分,那么这条弦所在的直线方程为()(\quad) A. 4x+3y−7=04x+3y-7=0 B. 4x−3y−7=04x-3y-7=0 C.…
  22. 22Points P, Q and R have coordinates (1,1)(1, 1), (5,11)(5, 11) and (9,1)(9, 1) respectively. M is the midpoint of QR. Find the coor…
  23. 23已知过两点A(−3,m)A(-3,m),B(m,5)B(m,5)的直线与直线3x+y−1=03x+y-1=0平行,则mm的值是()() A. 33 B. 77 C. −7-7 D. −9-9
  24. 24设双曲线x2a2−y2b2=1(a>0,b>0) \dfrac {x^{2}}{a^{2}}- \dfrac {y^{2}}{b^{2}}=1(a > 0,b > 0)的左、右顶点分别为AA、BB,点PP在双曲线上且异于AA、BB两点,OO…
  25. 25The gradient of the line joining the points (−3+2a,7)(-3+2a, 7) and (a+1,2)(a+1, 2) is −23-\frac{2}{3}. Find the value of a. Answer a…
  26. 26ABCD is a parallelogram. Point A lies on the y-axis and coordinates of D is (6, -1). AC is a horizontal line and gradien…
  27. 27Line l passes through the points (-4, 4) and (8, -2). Find the equation of line l. Answer ... The equation of line m is…
  28. 28The diagram shows a square ABCD. The diagonals of the square intersect at W and X is a point on the diagonal BD. Y lies…
  29. 29已知椭圆C:x2a2+y2b2=1(a>b>0)C: \dfrac {x^{2}}{a^{2}}+ \dfrac {y^{2}}{b^{2}}=1(a > b > 0)的左焦点F(−2,0)F(-2,0)左顶点A1(−4,0)A_{1}(-4,0). ((Ⅰ))求椭圆CC…
  30. 30The diagram shows the curve y = x^2 + px + q. The points A(0, −5) and B(2, −9) lie on the graph. B(2, −9) is the minimum…