Math topic中文

Formula nth term

Sequence given by a formula for the nnth term.

Practice questions

  1. 1Prove by the method of differences that ∑r=1N1r+r+1=N+1−1.\sum_{r=1}^{N} \frac{1}{\sqrt{r} + \sqrt{r+1}} = \sqrt{N+1} - 1.
  2. 2A sequence of numbers u1,u2,u3,…u_{1}, u_{2}, u_{3}, \ldots has sum SnS_{n} where Sn=∑r=1nurS_{n} = \sum_{r=1}^{n} u_{r}. It is given th…
  3. 3A sequence of numbers u1,u2,u3,…u_1, u_2, u_3, \dots has a sum SnS_n where Sn=∑r=1nurS_n = \sum_{r=1}^{n} u_r. It is given that Sn=An2(n+1)−BnS_n = An^2(n + 1) - Bn…
  4. 4By writing 3(3r+1)(3r+4)\frac{3}{(3r+1)(3r+4)} in partial fractions, find ∑r=1n3(3r+1)(3r+4)\sum_{r=1}^{n} \frac{3}{(3r+1)(3r+4)} in terms of nn.…
  5. 5A sequence is such that u0=2u_{0}=2 and un=un−1+n3+(12)nu_{n}=u_{n-1}+n^{3}+\left(\dfrac{1}{2}\right)^{n} for n≥1n\ge 1. (a) It is given…
  6. 6数列−1,5,−9,13,…{-}1{,}5{,}{-}9{,}13{,}{…}的一个通项公式是an=a_{n}{=} ___ .
  7. 7An arithmetic sequence has first term aa and common difference 0.50.5, where aa is an integer. Find the smallest value…
  8. 8The sum of the first nn terms of a sequence, SnS_n, is given by Sn=an3+bn2+cn+dS_n = an^3 + bn^2 + cn + d, where aa, bb, cc and dd…
  9. 9The first four terms of a sequence are given by v1=−9v_1 = -9, v2=7v_2 = 7, v3=47v_3 = 47 and v4=141v_4 = 141. It is given that vnv_n…
  10. 10数列{an}\{a_{n}\}中,Sn=4−an−12n−2S_{n}=4-a_{n}- \dfrac {1}{2^{n-2}}. ((Ⅰ))求a1a_{1},a2a_{2},a3a_{3},a4a_{4}; ((Ⅱ))…
  11. 11A sequence u1,u2,u3,…u_1, u_2, u_3, \dots is such that u1=12u_1 = \frac{1}{2} and un+1=un−n2+n−1(n+2)!,for all n≥1.u_{n+1} = u_n - \frac{n^2 + n - 1}{(n+2)!}, \quad \text{for all } n \ge 1.…
  12. 12A sequence u1,u2,u3,…u_1, u_2, u_3, \dots is such that un=2un−1−15n2+60n+Au_n = 2u_{n-1} - 15n^2 + 60n + A, where AA is a constant, and n≥2n \ge 2…
  13. 13已知等差数列{an}\{a_{n}\}的通项公式an=64−4n5a_{n}= \dfrac {64-4n}{5},设An=∣an+an+1+…+an+12∣(n∈N∗)A_{n}=|a_{n}+a_{n+1}+…+a_{n+12}|(n∈N^{*}),当AnA_{n}取得最小值时,nn…
  14. 14A sequence u1,u2,u3,…u_1, u_2, u_3, \dots is such that u1=0u_1 = 0 and un+1=un+4+n−n2[(n+1)(n+2)]2, for all n∈Z+.u_{n+1} = u_n + \frac{4 + n - n^2}{[(n+1)(n+2)]^2}, \text{ for all } n \in \mathbb{Z}^+.…
  15. 15Dendrologists are specialised scientists who study trees and woody plants. Their work is diverse and can encompass vario…
  16. 16Given that ∑n=1Nn3=[N2(N+1)]2,\sum_{n=1}^{N} n^{3} = \left[\frac{N}{2}(N+1)\right]^{2}, Find 12−23+33−43+⋯−(2N)3,1^{2}-2^{3}+3^{3}-4^{3}+\dots-(2N)^{3},…
  17. 17Prove that 2n+1n2+2n+n2−1=n2+2n−n2−1.\displaystyle \frac{2n+1}{\sqrt{n^2+2n+\sqrt{n^2-1}}} = \sqrt{n^2+2n} - \sqrt{n^2-1}. Hence find ∑n=1N2n+1n2+2n+n2−1\displaystyle \sum_{n=1}^N \frac{2n+1}{\sqrt{n^2+2n}+\sqrt{n^2-1}}…
  18. 18Prove by induction that ∑r=1nr3=14n2(n+1)2.\sum_{r=1}^{n} r^{3} = \frac{1}{4} n^{2} (n+1)^{2}. The r th term of a series is given by ln⁡(2ar)\ln\left(2a^{r}\right)…
  19. 19已知数列{an}\{a_{n}\}的前nn项为和SnS_{n},点(n,Snn)(n, \dfrac {S_{n}}{n})在直线y=12x+112y= \dfrac {1}{2}x+ \dfrac {11}{2}上.数列{bn}\{b_{n}\}…
  20. 20A sequence TnT_n is given by Tn=extln(na)+bn2+cT_n = ext{ln}(n^a) + bn^2 + c for nextoldsymbolmackslashinextoldsymbolmackslashZ+n ext{ } oldsymbol{ m ackslash in} ext{ } oldsymbol{ m ackslash Z}^+…
  21. 21A sequence follows the recurrence relation Un+1−Un=2cos⁡((2n+1)x2)sin⁡x2U_{n+1}-U_n = 2\cos\left(\dfrac{(2n+1)x}{2}\right)\sin\dfrac{x}{2}, U1=sin⁡xU_1 = \sin x…
  22. 22已知数列{an}\{a_{n}\}中,a1=1a_{1}=1,a2=2a_{2}=2,且an+1=4an−3an−1(n∈N∗,n⩾2)a_{n+1}=4a_{n}-3a_{n-1}(n∈N^{*},n\geqslant 2). ((Ⅰ))令bn=an+1−anb_{n}=a_{n+1}-a_{n}…
  23. 23Selena decides to borrow $200 000 from the bank to fund her home purchase on 1 January 2025. On the first day of each m…
  24. 24A sequence u1,u2,u3,…u_1, u_2, u_3, \dots is such that u1=e10u_1 = \dfrac{e}{10} and un−un−1=e2n−1u_n - u_{n-1} = \dfrac{e}{2^{n-1}}, for all n≥2n \ge 2…
  25. 25The reproduction number, R0R_0, of a disease is a mathematical term that indicates how contagious an infectious disease…
  26. 26Use the standard series for ln⁡(1+x)\ln(1+x) and ln⁡(1−x)\ln(1-x) to find the first three non-zero terms in the series for ln⁡(1+x1−x).\displaystyle\ln\left(\frac{1+x}{1-x}\right).…
  27. 27A bag contains 10 red and 15 green beads which are indistinguishable apart from colour. Beads are drawn from the bag sin…
  28. 28平面内有nn条直线,最多可将平面分成f(n)f(n)个区域,则f(n)f(n)的表达式为()(\quad) A. n+1          n+1\:\:\:\:\:\:\:\:\:\: B. 2n          2n\:\:\:\:\:\:\:\:\:\: …
  29. 29已知数列{an}\{a_{n}\}中,a1=2a_{1}=2,a2=3a_{2}=3,其前nn项和SnS_{n}满足Sn+1+Sn−1=2Sn+1S_{n+1}+S_{n-1}=2S_{n}+1,其中n⩾2n\geqslant 2,n∈N∗n∈N^{*}…
  30. 30Show that 1a+b=a−ba−b\dfrac{1}{\sqrt{a}+\sqrt{b}}=\dfrac{\sqrt{a}-\sqrt{b}}{a-b}. Find ∑r=1250014r−3+4r+1\displaystyle\sum_{r=1}^{2500}\dfrac{1}{\sqrt{4r-3}+\sqrt{4r+1}}…
  31. 31Find ∑r=0n[(n+2)r+n]\sum_{r=0}^{n} [(n+2)r + n], giving your answer in terms of nn. [You may use the result ∑r=1nr3=14n2(n+1)2\sum_{r=1}^{n} r^3 = \frac{1}{4}n^2(n+1)^2…
  32. 32A data processing centre processes data (in suitable units) every day. Let unu_n, where nn is an integer, n≥1n \ge 1, re…
  33. 33A sequence u1,u2,u3,…u_1,u_2,u_3,\dots is such that u1=34u_1 = \dfrac{3}{4} and un+1=un+34(12)2nu_{n+1} = u_n + \dfrac{3}{4}\left(\dfrac{1}{2}\right)^{2n}…
  34. 34Sarah, a Singaporean Citizen, started a 4-year undergraduate Computing course at the National University of Singapore (N…
  35. 35A sequence u0, u1, u2, …u_0,\ u_1,\ u_2,\ \dots is such that u0=0u_0 = 0 and un=un−1−2−n(n2−4n+2),for all n∈Z+.u_n = u_{n-1} - 2^{-n}\left(n^2 - 4n + 2\right),\quad\text{for all } n \in \mathbb{Z}^+.…
  36. 36The sum, SnS_{n}, of the first nn terms of a sequence u1,u2,u3,…u_{1}, u_{2}, u_{3}, \dots is given by Sn=a(3n)+bn+cS_{n}=a(3^{n})+bn+c, w…
  37. 37已知等差数列{an}\{a_{n}\}的首项a1=−2a_{1}=-2,等比数列{bn}\{b_{n}\}的公比为qq,且a2=b1a_{2}=b_{1},a3=b2+1a_{3}=b_{2}+1,a1b2+5b2=b3a_{1}b_{2}+5b_{2}=b_{3}…
  38. 38数列{an}\{a_{n}\}的通项公式是an=21+4n−n2a_{n}=21+4n-n^{2},这个数列从第 ___ 项起各项都为负数.
  39. 39It is given that f(r)=1−3(r+2)!\mathrm{f}(r) = 1 - \frac{3}{(r+2)!}, where rr is a non-negative integer. Show that f(r)−f(r−1)=a(r+1)(r+2)!\mathrm{f}(r) - \mathrm{f}(r-1) = \frac{a(r+1)}{(r+2)!}…
  40. 40已知f(x)=xexf(x)= \dfrac {x}{e^{x}},f1(x)=f′(x)f_{1}(x)=f′(x),f2(x)=[f1(x)]′f_{2}(x)=[f_{1}(x)]′,……,fn+1(x)=[fn(x)]′f_{n+1}(x)=[f_{n}(x)]′,n∈N∗n∈N^{*},经…
  41. 41The first nn terms of a series are given by log⁡a3+log⁡a27+log⁡a243+…+log⁡a32n−1\log_a 3 + \log_a 27 + \log_a 243 + \ldots + \log_a 3^{2^{n-1}}, where aa…
  42. 42Ryan has playing cards which he stacks into pyramids. He will begin by stacking up cards to form a pyramid with 1 level,…
  43. 43A geometric series has common ratio rr, and an arithmetic series has first term aa and common difference dd, where aa…
  44. 44At a particular bank, a savings account pays an interest of 0.9% per month on the last day of each month. On 1 January 2…
  45. 45A sequence is such that u0=2u_0 = 2 and un=un−1+n3+(12)nu_n = u_{n-1} + n^3 + \left(\frac{1}{2}\right)^n for n≥1n \ge 1. It is given that…
  46. 46已知数列{an}\{a_{n}\}的前nn项和为SnS_{n},Sn=2an−3n(n∈N∗).(1)S_{n}=2a_{n}-3n(n∈N^{*}).(1)证明数列{an+3}\{a_{n}+3\}是等比数列,求出数列{an}\{a_{n}\}的通项公式; (2…
  47. 47A sequence u1,u2,u3,…u_1, u_2, u_3, \dots is such that u1=13u_1 = \frac{1}{3} and ur+1=ur−1(2r−1)(2r+3),for all r≥1.u_{r+1} = u_r - \frac{1}{(2r-1)(2r+3)}, \quad \text{for all } r \ge 1.…
  48. 48A sequence u0,u1,u2,…u_0, u_1, u_2, \dots is such that u0=1u_0 = 1 and un=un−1+2n+1n(n+1),for all n∈N+.u_n = u_{n-1} + 2n + \frac{1}{n(n+1)}, \quad\text{for all } n \in \mathbb{N}^+.…
  49. 49The diagrams below show a sequence of patterns formed by squares. Stage 0 is represented by a square of length 1. At eac…
  50. 50It is given that ∑r=1n2r(r+1)(r+2)=12−1(n+1)(n+2).\sum_{r=1}^n \dfrac{2}{r(r+1)(r+2)} = \dfrac{1}{2} - \dfrac{1}{(n+1)(n+2)}. State the sum to infini…
  51. 51Prove by induction that, for all positive integers nn and for x∈Rx \in \mathbb{R}, x≠0,x≠1x \ne 0, x \ne 1, 1x−1−1x−1x2−⋯−1xn=1xn(x−1).\dfrac{1}{x-1}-\dfrac{1}{x}-\dfrac{1}{x^2}-\dots-\dfrac{1}{x^n}=\dfrac{1}{x^n(x-1)}.…
  52. 52A rice retailer pledges to donate a bowl of rice for every kilometre run by participants in a service-learning project.…
  53. 53The first nn terms of a series are given by log⁡a3+log⁡a27+log⁡a243+⋯+log⁡a32n−1\log_a 3 + \log_a 27 + \log_a 243 + \dots + \log_a 3^{2n-1}, where aa is…
  54. 54A sequence u1,u2,u3,…u_1, u_2, u_3, \dots is such that u1=−1u_1 = -1 and un+1=un+2(3−n)+au_{n+1} = u_n + 2(3^{-n}) + a, where n∈Z+n \in \mathbb{Z}^+…
  55. 55A series is given by ∑r=1n2(4−3x)r\sum_{r=1}^{n} 2(4-3x)^{r} where xx is constant. Explain why this is a geometric series. Deter…
  56. 56The ninth, fifth and second terms of an arithmetic progression are successive terms of a geometric progression with firs…
  57. 57The sum of the first nn terms of a sequence, uru_r, is given by ∑r=1nur=1−n(n+1)!\displaystyle\sum_{r=1}^n u_r = 1 - \dfrac{n}{(n+1)!}…
  58. 58Given that ∑r=1nr2=n(n+1)(2n+1)6,\sum_{r=1}^{n} r^{2} = \frac{n(n+1)(2n+1)}{6}, find ∑r=1n(3r+1)2\sum_{r=1}^{n} (3r+1)^{2} in terms of n. Use your…
  59. 59A sequence u1,u2,u3,…u_1, u_2, u_3, \dots satisfies the recurrence relation un=n(n−1)2un−1u_n = \frac{n}{(n-1)^2}u_{n-1}, for n≥2n \ge 2. Giv…
  60. 60已知数列{an}\{a_{n}\},an=1n(n+2)(n∈N+)a_{n}= \dfrac {1}{n(n+2)}(n∈N_{+}),那么1120 \dfrac {1}{120}是这个数列的第 ___ 项.