Math topic中文

Evaluating definite integrals

evaluation of definite integrals

Practice questions

  1. 1The figure shows part of the curve y=g(x)y = g(x). (2,8)(2, 8) and (6,1)(6, 1) are two points on the curve. Given that ∫26y dx=32\int_{2}^{6} y \text{ } dx = 32…
  2. 2A motorist, travelling at a constant velocity of V m/s, passed a fixed point X and saw few vehicles ahead. He stepped on…
  3. 3Express 8x+13(1+2x)(2+x)2\frac{8x+13}{(1+2x)(2+x)^2} in partial fractions. Express 8x+13(1+2x)(2+x)2\frac{8x+13}{(1+2x)(2+x)^2} in partial fractions…
  4. 4It is given that y=4xsin⁡2xy = 4x \sin 2x. Show that dydx\frac{\mathrm{d}y}{\mathrm{d}x} can be expressed in the form axcos⁡2x+bsin⁡2xax \cos 2x + b \sin 2x…
  5. 5Express 2x2+3xx2+3x+2\dfrac{2x^{2}+3x}{x^{2}+3x+2} in partial fractions. Hence evaluate ∫132x2+3xx2+3x+2 dx\displaystyle \int_{1}^{3} \dfrac{2x^{2}+3x}{x^{2}+3x+2}\,dx…
  6. 6The diagram shows part of the curve y=(1−x)(x−4)y = (1 - x)(x - 4) and two lines l1l_1 and l2l_2. The lines l1l_1 and l2l_2 are ta…
  7. 7A particle moves in a straight line, so that, tt seconds after leaving a fixed point OO its velocity, vv is given by…
  8. 8The diagram below shows the graph of y=12x+1y = \frac{1}{2x+1} and the tangent to the curve where the curve intersects the yy…
  9. 9Show that ddx(tan⁡32x)=6sec⁡42x−6sec⁡22x\frac{d}{dx}(\tan^{3} 2x) = 6\sec^{4} 2x - 6\sec^{2} 2x. Hence, find the exact value of ∫0π/8sec⁡42x dx\displaystyle \int_{0}^{\pi/8} \sec^{4} 2x\, dx…
  10. 10Express 2x+15(3+x)(3−2x)\frac{2x+15}{(3+x)(3-2x)} in partial fractions. Hence evaluate ∫012x+15(3+x)(3−2x) dx\int_{0}^{1} \frac{2x+15}{(3+x)(3-2x)} \, dx.
  11. 11The diagram shows part of the curve y=1(34x−5)2+1y = \frac{1}{\left(\frac{3}{4}x - 5\right)^2} + 1. PP is the point on the curve w…
  12. 12Differentiate 4xe3x4xe^{3x} with respect to xx. Hence, evaluate ∫036xe3xdx\int_{0}^{3} 6xe^{3x} \text{d}x, giving your answer in e…
  13. 13Differentiate 3xsin⁡2x3x \sin 2x with respect to xx. Hence, evaluate ∫0π4xcos⁡2x dx\int_{0}^{\frac{\pi}{4}} x \cos 2x \text{ d}x.
  14. 14∫−22(sin⁡x+4−x2)dx=()∫_{-2}^{2}(\sin x+\sqrt{4-x^{2}}){\rm d}x=(\quad) A. 44 B. 2π2π C. 4+2π4+2π D. 88
  15. 15Given that y=2cos⁡xsin⁡2x−sin⁡xcos⁡2xy = 2\cos x \sin 2x - \sin x \cos 2x, show that dydx=kcos⁡xcos⁡2x\dfrac{dy}{dx} = k\cos x \cos 2x, stating the value of kk…
  16. 16∫24x3−3x2+5x2dx\int _{2}^{4}\dfrac{{{x}^{3}}-3{{x}^{2}}+5}{{{x}^{2}}}dx的值为 ()() A. 11 B. 14\dfrac{1}{4} C. 54\dfrac{5}{4}…
  17. 17A particle moves in a straight line such that its velocity, v m/sv\text{ m/s}, is given by v=9sin⁡(t2)v = 9\sin\left(\frac{t}{2}\right)…
  18. 18The diagram shows part of the curve y=4−e−2xy = 4 - e^{-2x} which crosses the axes at AA and at BB. Find the coordinates of…
  19. 19The diagram shows part of the curve y=ex−1−2y = e^{x-1} - 2. The point P(2, e−2)P(2,\ e-2) lies on the curve and the normal to the cu…
  20. 20计算定积分 ∫02(3x2+2x) dx\displaystyle\int_0^2 (3x^2 + 2x) \, dx。
  21. 21Evaluate ∫0π3(12sin⁡3x−cos⁡2x)dx\int_{0}^{\frac{\pi}{3}} \left( \frac{1}{2} \sin 3x - \cos^2 x \right) dx, correct to 2 decimal places.
  22. 22Find the area of the shaded region. The figure above is not drawn to scale.
  23. 23Show that ddx(cot⁡x)=−csc⁡2x\dfrac{d}{dx}(\cot x) = -\csc^{2} x . Hence find the value of ∫π/4π/2−cot⁡2x dx\displaystyle \int_{\pi/4}^{\pi/2} -\cot^{2} x\, dx…
  24. 24The graph shows part of the curve y=−3(2x−4)−1/3y = -3(2x-4)^{-1/3}. The point P(−2, 1.5)P(-2,\ 1.5) lies on the curve and the normal to the…
  25. 25The diagram shows part of the curve y=2x+4y = \sqrt{2x + 4}, meeting the xx-axis at the point AA and the yy-axis at the p…
  26. 26The diagram shows part of the curve y=2sin⁡2x+1y = 2 \sin 2x + 1. PP is the maximum point of the curve and QQ is the point on t…
  27. 27The diagram shows part of the curve y=x3+3x2−2y = x^3 + 3x^2 - 2. The straight line LL cuts the curve at A(−3,−2)A(-3, -2), the x-axi…
  28. 28It is given that y=(x−3)x+1y = (x-3)\sqrt{x+1}. Find dydx\dfrac{dy}{dx} in the form ax−b2x+1\dfrac{ax-b}{2\sqrt{x+1}}, where aa and bb…
  29. 29The diagram shows part of the curve y=14x2−12ln⁡(x3)y = \frac{1}{4}x^2 - \frac{1}{2}\ln\left(\frac{x}{3}\right) and P(3, 2.25)P(3,\,2.25) is…
  30. 30The diagram shows part of the curve y=2sin⁡x2y = 2\sin\frac{x}{2}, where AA lies on the curve. The xx-coordinate of AA is 4π3\frac{4\pi}{3}…
  31. 31求曲线 y=x2y = x^2 与 y=2xy = 2x 围成的封闭图形的面积。
  32. 32Given that y=4x3−2xy = \dfrac{4x}{\sqrt{3-2x}}, show that dydx=12−4x(3−2x)3\dfrac{dy}{dx} = \dfrac{12-4x}{\sqrt{(3-2x)^3}}. Hence find the va…
  33. 33The diagram shows the curve y=cos⁡x+sin⁡xy = \cos x + \sin x for 0≤x≤π0 \le x \le \pi. The curve meets the yy-axis at the point AA a…
  34. 34Express 8−3x(2x+3)(x2+4)\dfrac{8 - 3x}{(2x + 3)(x^2 + 4)} in partial fractions. Differentiate ln⁡(x2+4)\ln\left(x^2 + 4\right) with respect t…
  35. 35The diagram shows part of the curve y=15(0.5x+1)y = \frac{15}{(0.5x+1)} and a straight line y=1.25x−10y = 1.25x - 10. The straight line in…
  36. 36Find ddx(3x2ln⁡x).Hencefind\dfrac{\mathrm{d}}{\mathrm{d}x}\left(3x^{2}\ln x\right). Hence find \int x\ln x,\mathrm{d}x.Thediagramshowstheline. The diagram shows the line …
  37. 37It is given that f(x)={4a2−x2for 0≤x≤2a,3x−6afor 2a<x<3a,f(x) = \begin{cases} \sqrt{4a^2 - x^2} & \text{for } 0 \le x \le 2a, \\ 3x - 6a & \text{for } 2a < x < 3a, \end{cases}…
  38. 38The diagram shows part of the curve y=52x−1y = \frac{5}{2x - 1}. The line 9y=−10x+559y = -10x + 55 intersects the curve at points AA…
  39. 39The diagram shows part of the curve y=76x+1y = \frac{7}{6x + 1} intersecting the yy-axis at A(0,7)A(0, 7). The tangent to the cu…
  40. 40已知aa是A=7n+Cn17n−1+Cn27n−2+⋯+Cnn−17(nA=7^{n}+C_{n}^{1}7^{n-1}+C_{n}^{2}7^{n-2}+⋯+C_{n}^{n-1}7(n为正奇数))被44整除的余数,则∫1e(x+ax)dx∫_{1}^{e}(x+\dfrac{a}{x}){\rm d}x…
  41. 41设a=∫0π(sin⁡x+cos⁡x)dxa= \int _{ 0 }^{ π }(\sin x+\cos x)dx,且二项式(ax−1x)n(a \sqrt {x}- \dfrac {1}{ \sqrt {x}})^{n}的所有二项式系数之和为6464,则其展开式中含x2x^{2}…
  42. 42Given that y=x22x−1y = x^2 \sqrt{2x-1}, show that dydx=x(5x−2)2x−1\frac{\text{d}y}{\text{d}x} = \frac{x(5x-2)}{\sqrt{2x-1}}. Determine wheth…
  43. 43Find ddx((2x−3)e2x).Henceevaluate\dfrac{\mathrm{d}}{\mathrm{d}x}\bigl((2x-3)e^{2x}\bigr). Hence evaluate \displaystyle\int_0^1 4xe^{2x},\mathrm{d…
  44. 44A particle PP moves in a straight line, so that, tt seconds after leaving a fixed point OO, its velocity, vv m/s, is…
  45. 45A particle moves from point P towards point O. The speed of the particle, tt seconds after passing point P, can be mode…
  46. 46Given that y=(x+2)x−1y = (x + 2)\sqrt{x - 1}, show that dydx=kx2x−1\frac{\text{d}y}{\text{d}x} = \frac{kx}{2\sqrt{x - 1}} where kk is co…
  47. 47The equation of a curve is y=1−sin⁡xcos⁡xy = \frac{1 - \sin x}{\cos x}. Show that dydx=tan⁡xsec⁡x−sec⁡2x\frac{dy}{dx} = \tan x \sec x - \sec^2 x. Hence…
  48. 48A scooter travelling up and down a straight horizontal road passes a fixed point O with a speed of p m s−1p\ \text{m s}^{-1}.…
  49. 49The diagram shows part of the curve y=(9−x)(x−3)y=(9-x)(x-3) and the line y=k−3y=k-3, where k>3k>3. The line through the maximum point…
  50. 50A particle moves in a straight line with a fixed point OO. The velocity of the particle, vv m/s, is given by v=252t+1+10v = \dfrac{25}{2t+1} + 10…
  51. 51Given that y=(2x−1)3ln⁡2x−1y = (2x - 1)^3 \ln \sqrt{2x - 1}. Show that dydx=6(2x−1)2ln⁡2x−1+(2x−1)2\frac{\text{d}y}{\text{d}x} = 6(2x - 1)^2 \ln \sqrt{2x - 1} + (2x - 1)^2…
  52. 52The graph shows the curve CC with equation y=x2y = x^2 and the line LL with equation y=2x−1y = 2x-1. The line LL is tangent…
  53. 53The diagram shows part of the curve y=3x−2y = \sqrt{3x-2}. The normal to the curve at BB meets the xx-axis at CC. Given t…
  54. 54The diagram shows the curve y=4−2cos⁡2xy = 4 - 2\cos 2x for 0≤x≤32π0 \le x \le \frac{3}{2}\pi radians and a straight line passing thro…
  55. 55Answer all questions. Differentiate 2xe1−2x2xe^{1-2x} with respect to xx. Hence find the exact value of ∫012xe1−2xdx\int_{0}^{1} 2xe^{1-2x} \text{d}x…
  56. 56Show that ddx[x(3x−2)43]=(7x−2)(3x−2)13\frac{d}{dx}\left[x(3x-2)^{\frac{4}{3}}\right] = (7x-2)(3x-2)^{\frac{1}{3}}. Hence evaluate ∫x(3x−2)13dx\int x(3x-2)^{\frac{1}{3}} dx…
  57. 57The diagram shows part of the curve y=2x+5y = \sqrt{2x+5}. A is a point on the curve and the x-coordinate of A is 2. The nor…
  58. 58The diagram shows part of the curve y=5+4e2xy = 5 + \frac{4}{e^{2x}} intersecting the yy-axis at point PP. The tangent to th…
  59. 59A particle travels in a straight line, so that tt seconds after passing a fixed point OO, its velocity, vv m/s, is gi…
  60. 60The diagram shows part of the curve of y=x(x−2)2y = x(x-2)^2, which passes through the point P(1,1)P(1, 1). Show that the equation…