Math topic中文

Integration linear argument

integration of (ax+b)n(ax + b)^{n} for any rational nn, sin⁡(ax+b)\sin(ax + b), cos⁡(ax+b)\cos(ax + b) and e(ax+b)e^{(ax + b)}

Practice questions

  1. 1The diagram shows part of the curve y=3e−12x−6y = 3e^{-\frac{1}{2}x} - 6 which crosses the xx-axis at PP and the yy-axis at QQ…
  2. 2Express x2+3x+2x2(2x+1)\dfrac{x^2+3x+2}{x^2(2x+1)} in partial fractions. Hence integrate x2+3x+2x2(2x+1)\dfrac{x^2+3x+2}{x^2(2x+1)} with respect t…
  3. 3A motorist, travelling at a constant velocity of V m/s, passed a fixed point X and saw few vehicles ahead. He stepped on…
  4. 4Express 8x+13(1+2x)(2+x)2\frac{8x+13}{(1+2x)(2+x)^2} in partial fractions. Express 8x+13(1+2x)(2+x)2\frac{8x+13}{(1+2x)(2+x)^2} in partial fractions…
  5. 5The equation of a curve is given by y=5xe2x+1y = 5xe^{2x+1}. Find dydx\frac{dy}{dx}. Hence, find ∫xe2x+1 dx\int xe^{2x+1} \text{ d}x. Det…
  6. 6The diagram shows part of the curve y=3x+4y = \sqrt{3x + 4}. The line ABAB is tangent to the curve at AA. The points BB an…
  7. 7It is given that f′(x)=6cos⁡3x−12sin⁡3xf'(x)=6\cos 3x-12\sin 3x and f(π3)=0f\left(\frac{\pi}{3}\right)=0. Find f(x)f(x). Find the exact value of f′′(π12)f''\left(\frac{\pi}{12}\right)…
  8. 8The gradient function of a curve y=f(x)y = f(x) is given by 36(2x+1)2\frac{36}{(2x+1)^2} for x>−12x > -\frac{1}{2}. The curve passes t…
  9. 9It is given that y=4xsin⁡2xy = 4x \sin 2x. Show that dydx\frac{\mathrm{d}y}{\mathrm{d}x} can be expressed in the form axcos⁡2x+bsin⁡2xax \cos 2x + b \sin 2x…
  10. 10Express 2x2+3xx2+3x+2\dfrac{2x^{2}+3x}{x^{2}+3x+2} in partial fractions. Hence evaluate ∫132x2+3xx2+3x+2 dx\displaystyle \int_{1}^{3} \dfrac{2x^{2}+3x}{x^{2}+3x+2}\,dx…
  11. 11It is given that f(x)f(x) is such that f′(x)=sin⁡2x+cos⁡3xf'(x) = \sin 2x + \cos 3x. Given also that f(π6)=0f\left(\frac{\pi}{6}\right) = 0, sho…
  12. 12A particle moves in a straight line, so that, tt seconds after leaving a fixed point OO its velocity, vv is given by…
  13. 13The diagram below shows the graph of y=12x+1y = \frac{1}{2x+1} and the tangent to the curve where the curve intersects the yy…
  14. 14Show that ddx(tan⁡32x)=6sec⁡42x−6sec⁡22x\frac{d}{dx}(\tan^{3} 2x) = 6\sec^{4} 2x - 6\sec^{2} 2x. Hence, find the exact value of ∫0π/8sec⁡42x dx\displaystyle \int_{0}^{\pi/8} \sec^{4} 2x\, dx…
  15. 15Express 2x+15(3+x)(3−2x)\frac{2x+15}{(3+x)(3-2x)} in partial fractions. Hence evaluate ∫012x+15(3+x)(3−2x) dx\int_{0}^{1} \frac{2x+15}{(3+x)(3-2x)} \, dx.
  16. 16The diagram shows part of the curve y=1(34x−5)2+1y = \frac{1}{\left(\frac{3}{4}x - 5\right)^2} + 1. PP is the point on the curve w…
  17. 17Differentiate 4xe3x4xe^{3x} with respect to xx. Hence, evaluate ∫036xe3xdx\int_{0}^{3} 6xe^{3x} \text{d}x, giving your answer in e…
  18. 18Differentiate 3xsin⁡2x3x \sin 2x with respect to xx. Hence, evaluate ∫0π4xcos⁡2x dx\int_{0}^{\frac{\pi}{4}} x \cos 2x \text{ d}x.
  19. 19A particle passes a fixed point OO and moves in a straight line such that, tt s after leaving OO, its velocity, v m/sv\text{ m/s}…
  20. 20A particle moves in a straight line such that its velocity, v m/sv\text{ m/s}, is given by v=9sin⁡(t2)v = 9\sin\left(\frac{t}{2}\right)…
  21. 21The diagram shows part of the curve y=4−e−2xy = 4 - e^{-2x} which crosses the axes at AA and at BB. Find the coordinates of…
  22. 22The diagram shows part of the curve y=ex−1−2y = e^{x-1} - 2. The point P(2, e−2)P(2,\ e-2) lies on the curve and the normal to the cu…
  23. 23Evaluate ∫0π3(12sin⁡3x−cos⁡2x)dx\int_{0}^{\frac{\pi}{3}} \left( \frac{1}{2} \sin 3x - \cos^2 x \right) dx, correct to 2 decimal places.
  24. 24It is given that f(x)\mathrm{f}(x) is such that f′(x)=3sin⁡xcos⁡x\mathrm{f}'(x) = 3 \sin x \cos x and (π2,1)\left(\frac{\pi}{2}, 1\right) is…
  25. 25The diagram shows part of the curve y=4x+5y = \sqrt{4x + 5}. The normal of the curve at PP meets the xx-axis at TT. The xx…
  26. 26A curve is such that d2ydx2=6e3x−x\frac{d^2y}{dx^2} = 6e^{3x} - x and passes through the point (2,23e6)\left(2, \frac{2}{3}e^6\right). Gi…
  27. 27Find the area of the shaded region. The figure above is not drawn to scale.
  28. 28The graph shows part of the curve y=−3(2x−4)−1/3y = -3(2x-4)^{-1/3}. The point P(−2, 1.5)P(-2,\ 1.5) lies on the curve and the normal to the…
  29. 29The diagram shows part of the curve y=2x+4y = \sqrt{2x + 4}, meeting the xx-axis at the point AA and the yy-axis at the p…
  30. 30The diagram shows part of the curve y=2sin⁡2x+1y = 2 \sin 2x + 1. PP is the maximum point of the curve and QQ is the point on t…
  31. 31Find ddx(xcos⁡2x)\frac{\text{d}}{\text{d}x}(x \cos 2x). Find ddx(x2sin⁡2x)\frac{\text{d}}{\text{d}x}(x^2 \sin 2x). Using the results to parts…
  32. 32It is given that y=(x−3)x+1y = (x-3)\sqrt{x+1}. Find dydx\dfrac{dy}{dx} in the form ax−b2x+1\dfrac{ax-b}{2\sqrt{x+1}}, where aa and bb…
  33. 33The diagram shows part of the curve y=2sin⁡x2y = 2\sin\frac{x}{2}, where AA lies on the curve. The xx-coordinate of AA is 4π3\frac{4\pi}{3}…
  34. 34Express 8−3x(2x+3)(x2+4)\dfrac{8 - 3x}{(2x + 3)(x^2 + 4)} in partial fractions. Differentiate ln⁡(x2+4)\ln\left(x^2 + 4\right) with respect t…
  35. 35The gradient function of a curve is 3cos⁡4x−sec⁡23x3\cos 4x - \sec^2 3x. Given that the curve passes through the point (π12,34−13)\left(\frac{\pi}{12}, \frac{\sqrt{3}}{4} - \frac{1}{3}\right)…
  36. 36The diagram shows part of the curve y=15(0.5x+1)y = \frac{15}{(0.5x+1)} and a straight line y=1.25x−10y = 1.25x - 10. The straight line in…
  37. 37A particular curve for which d2ydx2=sin⁡3x−cos⁡12x\frac{d^2y}{dx^2} = \sin 3x - \cos \frac{1}{2}x passes through the point Q(π3,23)Q\left(\frac{\pi}{3}, 2\sqrt{3}\right)…
  38. 38Show that ddx[(2x)(3−5x)65]=(6−22x)(3−5x)15\frac{d}{dx} \left[ (2x)(3-5x)^{\frac{6}{5}} \right] = (6-22x)(3-5x)^{\frac{1}{5}}. Hence, evaluate ∫x(3−5x)15dx\int x(3-5x)^{\frac{1}{5}} dx…
  39. 39The diagram shows part of the curve y=52x−1y = \frac{5}{2x - 1}. The line 9y=−10x+559y = -10x + 55 intersects the curve at points AA…
  40. 40The diagram shows part of the curve y=76x+1y = \frac{7}{6x + 1} intersecting the yy-axis at A(0,7)A(0, 7). The tangent to the cu…
  41. 41A particle moves in a straight line such that, tt s after passing through a fixed point OO, its displacement from OO…
  42. 42By using a suitable substitution, or otherwise, solve the equation 3log⁡6x=log⁡x3+log⁡x2+log⁡525.3\log_6 x = \log_x 3 + \log_x 2 + \log_5 25. Sket…
  43. 43Given that y=sec⁡xy = \sec x, show that dydx=sec⁡xtan⁡x\frac{dy}{dx} = \sec x \tan x. Hence show that y4−y2=(dydx)2y^4 - y^2 = \left(\frac{dy}{dx}\right)^2…
  44. 44Express 13x−6x2(2x−3)\frac{13x - 6}{x^2(2x - 3)} in partial fractions. Hence ∫13x−6x2(2x−3) dx\int \frac{13x - 6}{x^2(2x - 3)} \, dx.
  45. 45A curve is such that d2ydx2=36e3x−e−x\frac{d^2y}{dx^2} = 36e^{3x} - e^{-x}. The curve intersects the yy-axis at Q(0,5)Q(0, 5) and the tan…
  46. 46Given that y=x22x−1y = x^2 \sqrt{2x-1}, show that dydx=x(5x−2)2x−1\frac{\text{d}y}{\text{d}x} = \frac{x(5x-2)}{\sqrt{2x-1}}. Determine wheth…
  47. 47A particle PP moves in a straight line, so that, tt seconds after leaving a fixed point OO, its velocity, vv m/s, is…
  48. 48A particle moves from point P towards point O. The speed of the particle, tt seconds after passing point P, can be mode…
  49. 49Differentiate 2xcos⁡3x2x \cos 3x with respect to xx. Hence, find ∫xsin⁡3x dx\int x \sin 3x \text{ d}x.
  50. 50Integrate 4x2−31−5x+sin⁡5x−π\frac{4}{x^2} - \frac{3}{1 - 5x} + \sin 5x - \pi with respect to xx.
  51. 51The equation of a curve is y=1−sin⁡xcos⁡xy = \frac{1 - \sin x}{\cos x}. Show that dydx=tan⁡xsec⁡x−sec⁡2x\frac{dy}{dx} = \tan x \sec x - \sec^2 x. Hence…
  52. 52Express 3x2−4x2(3x−2)\frac{3x^2 - 4}{x^2(3x - 2)} in partial fractions. Hence, evaluate ∫3x2−4x2(3x−2) dx\int \frac{3x^2 - 4}{x^2(3x - 2)} \, dx.
  53. 53A scooter travelling up and down a straight horizontal road passes a fixed point O with a speed of p m s−1p\ \text{m s}^{-1}.…
  54. 54Express 9x2+17x−163x2+5x−2\frac{9x^2 + 17x - 16}{3x^2 + 5x - 2} in partial fractions. Hence, find ∫9x2+17x−163x2+5x−2 dx\int \frac{9x^2 + 17x - 16}{3x^2 + 5x - 2} \, dx…
  55. 55Express 2x3+x2+x(x−1)(x2+1)\frac{2x^3 + x^2 + x}{(x-1)(x^2 + 1)} in partial fractions. Differentiate ln⁡(x2+1)\ln(x^2 + 1) with respect to xx.…
  56. 56A particle moves in a straight line with a fixed point OO. The velocity of the particle, vv m/s, is given by v=252t+1+10v = \dfrac{25}{2t+1} + 10…
  57. 57Given that y=(2x−1)3ln⁡2x−1y = (2x - 1)^3 \ln \sqrt{2x - 1}. Show that dydx=6(2x−1)2ln⁡2x−1+(2x−1)2\frac{\text{d}y}{\text{d}x} = 6(2x - 1)^2 \ln \sqrt{2x - 1} + (2x - 1)^2…
  58. 58Integrate (6e3−x)2\left(\frac{6}{e^{3-x}}\right)^2 with respect to xx. Explain, with working, why the equation 2x3+3x2+2x+8=02x^3 + 3x^2 + 2x + 8 = 0…
  59. 59The diagram shows part of the curve y=3x−2y = \sqrt{3x-2}. The normal to the curve at BB meets the xx-axis at CC. Given t…
  60. 60It is given that f′(x)=sin⁡3x−12x+1f'(x) = \sin 3x - \frac{1}{2x + 1} and f(0)=23f(0) = \frac{2}{3}. Find an expression for 6f(x)+f′′(x)6f(x) + f''(x).