Math topic中文

Standard integrals

integration of xnx^{n} for any rational nn, sin⁡x\sin x, cos⁡x\cos x, sec⁡2x\sec^{2}x and exe^{x}, together with constant multiples, sums and differences

Practice questions

  1. 1Given that y=3ln⁡2xx2y = \dfrac{3\ln 2x}{x^2} for x>0x>0. Show that dydx=3x3(1−2ln⁡2x).\dfrac{dy}{dx} = \dfrac{3}{x^3}\left(1 - 2\ln 2x\right). He…
  2. 2The figure shows part of the curve y=g(x)y = g(x). (2,8)(2, 8) and (6,1)(6, 1) are two points on the curve. Given that ∫26y dx=32\int_{2}^{6} y \text{ } dx = 32…
  3. 3Express x2+3x+2x2(2x+1)\dfrac{x^2+3x+2}{x^2(2x+1)} in partial fractions. Hence integrate x2+3x+2x2(2x+1)\dfrac{x^2+3x+2}{x^2(2x+1)} with respect t…
  4. 4A particle starts from rest from a point OO and moves in a straight line such that its velocity vv m/s, is given by v=24t−6t2v = 24t - 6t^2…
  5. 5The equation of a curve is given by y=5xe2x+1y = 5xe^{2x+1}. Find dydx\frac{dy}{dx}. Hence, find ∫xe2x+1 dx\int xe^{2x+1} \text{ d}x. Det…
  6. 6A particle, P, starts moving in a straight line with a velocity of 8 m/s at a displacement of 3 m from a fixed point O.…
  7. 7A particle PP moves in a straight line so that, tt seconds after passing through a fixed point OO, its velocity vv m…
  8. 8Differentiate ln⁡(3xx2+1)\ln\left(\frac{3x}{x^2+1}\right) with respect to xx. Hence find ∫2xx2+1 dx\displaystyle \int \frac{2x}{x^2+1}\,dx…
  9. 9Show that ddx(tan⁡32x)=6sec⁡42x−6sec⁡22x\frac{d}{dx}(\tan^{3} 2x) = 6\sec^{4} 2x - 6\sec^{2} 2x. Hence, find the exact value of ∫0π/8sec⁡42x dx\displaystyle \int_{0}^{\pi/8} \sec^{4} 2x\, dx…
  10. 10Given that y=2cos⁡xsin⁡2x−sin⁡xcos⁡2xy = 2\cos x \sin 2x - \sin x \cos 2x, show that dydx=kcos⁡xcos⁡2x\dfrac{dy}{dx} = k\cos x \cos 2x, stating the value of kk…
  11. 11∫24x3−3x2+5x2dx\int _{2}^{4}\dfrac{{{x}^{3}}-3{{x}^{2}}+5}{{{x}^{2}}}dx的值为 ()() A. 11 B. 14\dfrac{1}{4} C. 54\dfrac{5}{4}…
  12. 12Answer all the questions A curve has an equation y=2x2x+1y = 2x\sqrt{2x+1}. Show that dydx=ax+b2x+1\frac{dy}{dx} = \frac{ax+b}{\sqrt{2x+1}}…
  13. 13The gradient function of a curve is given by dydx=16x3−4\frac{\text{d}y}{\text{d}x} = \frac{16}{x^3} - 4. Given that the line 2y−x−6=02y - x - 6 = 0…
  14. 14计算定积分 ∫02(3x2+2x) dx\displaystyle\int_0^2 (3x^2 + 2x) \, dx。
  15. 15A particle P moves along a horizontal straight line so that t seconds after motion has begun, its displacement, s m, fro…
  16. 16A curve is such that d2ydx2=6e3x−x\frac{d^2y}{dx^2} = 6e^{3x} - x and passes through the point (2,23e6)\left(2, \frac{2}{3}e^6\right). Gi…
  17. 17A particle moves in a straight line so that its velocity, vv m/s is given by v=t2−4t+3v = t^2 - 4t + 3, where tt is the time…
  18. 18A particle travels in a straight line so that, tt seconds after leaving a fixed point OO, its velocity, v m s−1v\text{ m s}^{-1}…
  19. 19Find the area of the shaded region. The figure above is not drawn to scale.
  20. 20Show that ddx(cot⁡x)=−csc⁡2x\dfrac{d}{dx}(\cot x) = -\csc^{2} x . Hence find the value of ∫π/4π/2−cot⁡2x dx\displaystyle \int_{\pi/4}^{\pi/2} -\cot^{2} x\, dx…
  21. 21A cyclist moves along a straight road from home OO. His velocity, v m/minv\text{ m/min}, is given by v=25+10t−3t2v = 25 + 10t - 3t^2,…
  22. 22The diagram shows part of the curve y=x3+3x2−2y = x^3 + 3x^2 - 2. The straight line LL cuts the curve at A(−3,−2)A(-3, -2), the x-axi…
  23. 23Find ddx(xcos⁡2x)\frac{\text{d}}{\text{d}x}(x \cos 2x). Find ddx(x2sin⁡2x)\frac{\text{d}}{\text{d}x}(x^2 \sin 2x). Using the results to parts…
  24. 24The diagram shows part of the curve y=14x2−12ln⁡(x3)y = \frac{1}{4}x^2 - \frac{1}{2}\ln\left(\frac{x}{3}\right) and P(3, 2.25)P(3,\,2.25) is…
  25. 25Given that y=ex(1+cos⁡x)y = e^x (1+\cos x), show dydx=ex(1+cos⁡x−sin⁡x)\dfrac{dy}{dx} = e^x (1+\cos x - \sin x). Hence find ∫ex(cos⁡x−sin⁡x) dx\displaystyle \int e^x (\cos x - \sin x)\,dx…
  26. 26The diagram shows the curve y=cos⁡x+sin⁡xy = \cos x + \sin x for 0≤x≤π0 \le x \le \pi. The curve meets the yy-axis at the point AA a…
  27. 27The diagram shows part of the curve y=15(0.5x+1)y = \frac{15}{(0.5x+1)} and a straight line y=1.25x−10y = 1.25x - 10. The straight line in…
  28. 28Find ddx(3x2ln⁡x).Hencefind\dfrac{\mathrm{d}}{\mathrm{d}x}\left(3x^{2}\ln x\right). Hence find \int x\ln x,\mathrm{d}x.Thediagramshowstheline. The diagram shows the line …
  29. 29The diagram shows part of the curve y=52x−1y = \frac{5}{2x - 1}. The line 9y=−10x+559y = -10x + 55 intersects the curve at points AA…
  30. 30A curve is such that f′′(x)=6x−10\mathrm{f}''(x) = 6x - 10. The tangent to the curve y=f(x)y = \mathrm{f}(x) at the point (1,−2)(1, -2) pa…
  31. 31A particle PP travels in a straight line and its velocity, vv m/s, is given by v=4sin⁡2(t2)−1v = 4\sin^2\left(\frac{t}{2}\right) - 1…
  32. 32Express 13x−6x2(2x−3)\frac{13x - 6}{x^2(2x - 3)} in partial fractions. Hence ∫13x−6x2(2x−3) dx\int \frac{13x - 6}{x^2(2x - 3)} \, dx.
  33. 33A curve is such that d2ydx2=36e3x−e−x\frac{d^2y}{dx^2} = 36e^{3x} - e^{-x}. The curve intersects the yy-axis at Q(0,5)Q(0, 5) and the tan…
  34. 34A particle moving in a straight line, passes through a fixed point OO with a velocity of 4 m/s4\text{ m/s}. Its accelerati…
  35. 35Find ddx((2x−3)e2x).Henceevaluate\dfrac{\mathrm{d}}{\mathrm{d}x}\bigl((2x-3)e^{2x}\bigr). Hence evaluate \displaystyle\int_0^1 4xe^{2x},\mathrm{d…
  36. 36Differentiate xsin⁡x+cos⁡xx \sin x + \cos x with respect to xx. Show that ddx(13xsin⁡3x)=13sin⁡3x−xcos⁡3x+xcos⁡x\frac{\text{d}}{\text{d}x} \left( \frac{1}{3} x \sin^3 x \right) = \frac{1}{3} \sin^3 x - x \cos^3 x + x \cos x…
  37. 37Given that y=(x+2)x−1y = (x + 2)\sqrt{x - 1}, show that dydx=kx2x−1\frac{\text{d}y}{\text{d}x} = \frac{kx}{2\sqrt{x - 1}} where kk is co…
  38. 38Integrate 4x2−31−5x+sin⁡5x−π\frac{4}{x^2} - \frac{3}{1 - 5x} + \sin 5x - \pi with respect to xx.
  39. 39The equation of a curve is y=1−sin⁡xcos⁡xy = \frac{1 - \sin x}{\cos x}. Show that dydx=tan⁡xsec⁡x−sec⁡2x\frac{dy}{dx} = \tan x \sec x - \sec^2 x. Hence…
  40. 40A curve is such that d2ydx2=4−3x\dfrac{d^2y}{dx^2} = 4 - 3x and the point P(2,5)P(2,5) lies on the curve. The gradient of the curve a…
  41. 41Express 3x2−4x2(3x−2)\frac{3x^2 - 4}{x^2(3x - 2)} in partial fractions. Hence, evaluate ∫3x2−4x2(3x−2) dx\int \frac{3x^2 - 4}{x^2(3x - 2)} \, dx.
  42. 42For a particular curve d2ydx2=3x−2\frac{\text{d}^2 y}{\text{d}x^2} = 3x - 2. The tangent to the curve at the point A(4,−40)A(4, -40) is…
  43. 43The diagram shows part of the curve y=(9−x)(x−3)y=(9-x)(x-3) and the line y=k−3y=k-3, where k>3k>3. The line through the maximum point…
  44. 44Integrate (x−52x)2\left(x - \frac{5}{2x}\right)^2 with respect to xx.
  45. 45Express 2x3+x2+x(x−1)(x2+1)\frac{2x^3 + x^2 + x}{(x-1)(x^2 + 1)} in partial fractions. Differentiate ln⁡(x2+1)\ln(x^2 + 1) with respect to xx.…
  46. 46f(x)f(x) is such that f′′(x)=18x−4f''(x) = 18x - 4. Given that f(0)=1f(0) = 1 and f(2)=9f(2) = 9, find f(x)f(x). Show that x+1x + 1 is a factor…
  47. 47Integrate (6e3−x)2\left(\frac{6}{e^{3-x}}\right)^2 with respect to xx. Explain, with working, why the equation 2x3+3x2+2x+8=02x^3 + 3x^2 + 2x + 8 = 0…
  48. 48A particle XX travels in a straight line so that tt seconds after leaving a fixed point OO, its velocity vv m/s, is…
  49. 49Show that ddx(ln⁡xx4)=1x5−4ln⁡xx5\frac{d}{dx}\left(\frac{\ln x}{x^4}\right) = \frac{1}{x^5} - \frac{4\ln x}{x^5}. Given that the curve y=f(x)y = \mathrm{f}(x)…
  50. 50The diagram shows the curve y=4−2cos⁡2xy = 4 - 2\cos 2x for 0≤x≤32π0 \le x \le \frac{3}{2}\pi radians and a straight line passing thro…
  51. 51The gradient function of a curve is given by dydx=−1x2+6cos⁡3x\frac{dy}{dx} = -\frac{1}{x^2} + 6 \cos 3x. The coordinates of the point…
  52. 52A particle moves in a straight line, so that tt seconds after passing through a fixed point OO, its acceleration, a ms−2a\text{ ms}^{-2}…
  53. 53Show that ddx[x(3x−2)43]=(7x−2)(3x−2)13\frac{d}{dx}\left[x(3x-2)^{\frac{4}{3}}\right] = (7x-2)(3x-2)^{\frac{1}{3}}. Hence evaluate ∫x(3x−2)13dx\int x(3x-2)^{\frac{1}{3}} dx…
  54. 54Integrate 82x−1+4x3+1\frac{8}{2x-1} + \frac{4}{x^3} + 1 with respect to xx.
  55. 55Express 10x3−5x\frac{10x}{3-5x} in the form a+b3−5xa + \frac{b}{3-5x}, where aa and bb are integers. Hence, integrate 10x3−5x\frac{10x}{3-5x}…
  56. 56By using long division, divide 4x3+5x2+x−14x^3 + 5x^2 + x - 1 by x2(x+1)x^2 (x+1). Hence, express 4x3+5x2+x−1x2(x+1)\dfrac{4x^3 + 5x^2 + x - 1}{x^2 (x+1)}…
  57. 57A particle travels in a straight line, so that tt seconds after passing a fixed point OO, its velocity, vv m/s, is gi…
  58. 58The diagram shows part of the curve of y=x(x−2)2y = x(x-2)^2, which passes through the point P(1,1)P(1, 1). Show that the equation…
  59. 59A curve y=f(x)y = \text{f}(x) is such that f′′(x)=12e3x+7\text{f}''(x) = 12\text{e}^{3x} + 7 and the point A(0,−23)A\left(0, -\frac{2}{3}\right)…
  60. 60A curve is such that dydx=2x2+3(7−2x)\frac{dy}{dx} = \frac{2}{x^2} + \frac{3}{(7 - 2x)} and P(3,1)P(3, 1) is a point on the curve. Find th…