Argand diagram representation Representation of complex numbers in the Argand diagram. A complex number z = x + i y z = x + iy z = x + i y is represented as the point ( x , y ) (x, y) ( x , y ) (or the corresponding position vector) in the Argand plane, with the real part on the horizontal axis and the imaginary part on the vertical axis.
Practice questions 1 Solve the equation i z 5 = − 32 i z^5 = -32 i z 5 = − 32 , giving your roots in the form r e i θ re^{i\theta} r e i θ , where r > 0 r>0 r > 0 and − π < θ ≤ π -\pi<\theta\le\pi − π < θ ≤ π . Ske… 2 One of the roots of the equation 2 z 4 − 14 z 3 + 33 z 2 − 26 z + p = 0 , where p is a constant 2z^4 - 14z^3 + 33z^2 - 26z + p = 0\text{, where } p \text{ is a constant} 2 z 4 − 14 z 3 + 33 z 2 − 26 z + p = 0 , where p is a constant is 3 + i 3 + \mathrm{i} 3 + i … 3 One of the roots of the equation 2 z 4 − 14 z 3 + 33 z 2 − 26 z + p = 0 , where p is a constant 2z^{4} - 14z^{3} + 33z^{2} - 26z + p = 0\text{, where } p \text{ is a constant} 2 z 4 − 14 z 3 + 33 z 2 − 26 z + p = 0 , where p is a constant is… 4 Find, in a simplified form, the cartesian equation of the locus of the point P representing the complex number z where ∣ z + 3 ∣ = 2 ℜ ( z ) |z+3|=2\,\Re(z) ∣ z + 3∣ = 2 ℜ ( z ) … 5 在复平面内,复数z = 1 3 + i z= \dfrac {1}{3+i} z = 3 + i 1 对应的点位于( ) () ( ) A. 第一象限 B. 第二象限 C. 第三象限 D. 第四象限 6 The complex number z z z satisfies arg ( z − 1 − 2 i ) = θ \arg(z-1-2i)=\theta arg ( z − 1 − 2 i ) = θ , where θ \theta θ is a fixed angle in the interval − π < θ ≤ π -\pi < \theta \le \pi − π < θ ≤ π … 7 The equation z 3 − 2 z + k = 0 z^{3}-2z+k=0 z 3 − 2 z + k = 0 , where k k k is a real constant, has a root z = 1 + a i z = 1 + ai z = 1 + ai , where a a a is a positive real constan… 8 Sketch on a single Argand diagram, the loci defined by − π 4 < arg ( z + 1 + 2 i ) ≤ π 4 -\frac{\pi}{4} < \arg(z + 1 + 2\text{i}) \le \frac{\pi}{4} − 4 π < arg ( z + 1 + 2 i ) ≤ 4 π and… 9 Solve the equation i z 5 = − 32 iz^5=-32 i z 5 = − 32 , giving your roots in the form r e i θ re^{i\theta} r e i θ , where r > 0 r>0 r > 0 and − π < θ ≤ π -\pi<\theta\le\pi − π < θ ≤ π . Sketch… 10 The complex number a a a has modulus r r r and argument θ \theta θ , where r ∈ R + r \in \mathbb{R}^+ r ∈ R + and 0 < θ < π 2 0 < \theta < \frac{\pi}{2} 0 < θ < 2 π … 11 The point A represents a fixed complex number a such that − π 2 < arg a < 0 -\dfrac{\pi}{2}<\arg a<0 − 2 π < arg a < 0 . The complex numbers i a ia ia and a + i a a+ia a + ia … 12 The point A A A represents the complex number a a a with ∣ a ∣ = 1 |a|=1 ∣ a ∣ = 1 and θ = arg ( a ) , 0 < θ < π 4 \theta=\arg(a),\; 0<\theta<\dfrac{\pi}{4} θ = arg ( a ) , 0 < θ < 4 π . The point… 13 A complex number z z z varies with t t t such that z = 2 cos t + i ( 3 sin t ) , where 0 ≤ t < 2 π . z = 2\cos t + \mathrm{i}(3\sin t), \quad \text{where } 0 \le t < 2\pi. z = 2 cos t + i ( 3 sin t ) , where 0 ≤ t < 2 π . … 14 Solve the equation z 5 + 16 = 16 3 i z^5 + 16 = 16\sqrt{3}\, i z 5 + 16 = 16 3 i , giving the roots in the form r e i θ r e^{i\theta} r e i θ , where r > 0 r>0 r > 0 and − π < θ ≤ π -\pi < \theta \le \pi − π < θ ≤ π … 15 The complex numbers a a a and b b b are given by a = − ( 1 + 3 i ) a = -(1 + \sqrt{3}\text{i}) a = − ( 1 + 3 i ) and b = 1 2 ( 1 − i ) b = \frac{1}{2}(1 - \text{i}) b = 2 1 ( 1 − i ) . Without… 16 On a single Argand diagram, sketch the locus of points representing the complex number z z z such that ∣ z − 4 − 2 i ∣ ≤ 2 and ∣ z − 3 ∣ ≤ ∣ z − 5 ∣ . |z-4-2i| \le 2\quad\text{and}\quad |z-3| \le |z-5|. ∣ z − 4 − 2 i ∣ ≤ 2 and ∣ z − 3∣ ≤ ∣ z − 5∣. … 17 The complex number z z z satisfies the relations ∣ z ∣ ≤ 2 |z|\le 2 ∣ z ∣ ≤ 2 and π 6 ≤ arg z ≤ π 2 \dfrac{\pi}{6}\le \arg z \le \dfrac{\pi}{2} 6 π ≤ arg z ≤ 2 π . Illustrate… 18 Given that z = λ − 4 i 1 − λ i z = \frac{\lambda - 4i}{1 - \lambda i} z = 1 − λi λ − 4 i , λ ∈ R \lambda \in \mathbb{R} λ ∈ R and arg ( z ) = π \arg(z) = \pi arg ( z ) = π , find the value of z z z … 19 Do not use a calculator in answering this question. The complex number z z z has modulus 1 and argument θ \theta θ , where π 2 < θ < π \dfrac{\pi}{2}<\theta<\pi 2 π < θ < π … 20 The complex number z z z satisfies ∣ z − 4 − 3 i ∣ ≤ 2 and π < arg [ ( z − 4 ) 2 ] < 2 π |z-4-3\text{i}| \le 2 \quad \text{and} \quad \pi < \arg\left[(z-4)^2\right] < 2\pi ∣ z − 4 − 3 i ∣ ≤ 2 and π < arg [ ( z − 4 ) 2 ] < 2 π … 21 The points P and Q are represented by the complex numbers p and q respectively, where p = 2 + 2 i , arg ( q ) = 2 3 π and ∣ q ∣ = 2. p=\sqrt{2}+\sqrt{2}i\,,\ \arg(q)=\dfrac{2}{3}\pi\text{ and }|q|=2. p = 2 + 2 i , arg ( q ) = 3 2 π and ∣ q ∣ = 2. … 22 One of the roots of the equation 2 z 4 − 14 z 3 + 33 z 2 − 26 z + p = 0 , 2z^{4} - 14z^{3} + 33z^{2} - 26z + p = 0, 2 z 4 − 14 z 3 + 33 z 2 − 26 z + p = 0 , where p p p is a constant, is 3 + i 3 + i 3 + i . Base… 23 The point A on the Argand diagram below represents the complex number w 1 w_1 w 1 with modulus r r r and argument θ \theta θ . It i… 24 The three distinct roots of the equation x 3 − 1 = 0 x^3 - 1 = 0 x 3 − 1 = 0 are denoted by 1 , ω 1, \omega 1 , ω and ω 2 \omega^2 ω 2 . Without first finding… 25 A complex number z z z varies with t t t such that z = 2 cos t + i ( 3 sin t ) , where 0 ≤ t < 2 π . z = 2\cos t + i(3\sin t),\quad \text{where } 0 \le t < 2\pi. z = 2 cos t + i ( 3 sin t ) , where 0 ≤ t < 2 π . By takin… 26 Solve the equation z 4 = 3 − i z^4 = \sqrt{3} - i z 4 = 3 − i , giving the roots in the form r e i θ re^{i\theta} r e i θ where r > 0 r > 0 r > 0 and − π < θ ≤ π -\pi < \theta \le \pi − π < θ ≤ π … 27 The complex numbers z z z and w w w are such that z = 1 + i a , w = − b − i z = 1 + i a, \quad w = -b - i z = 1 + ia , w = − b − i where a a a and b b b are real and positive. G… 28 Do not use a calculator in answering this question. The complex number z z z has modulus 1 and argument θ \theta θ , wher…29 Do not use a calculator in answering this question. The complex numbers z z z and w w w have the same modulus r r r , and have… 30 On a single Argand diagram, sketch the following loci: ∣ z − 3 ∣ = 5 |z - 3| = 5 ∣ z − 3∣ = 5 arg ( z − 8 ) = π − tan − 1 ( 1 2 ) \arg(z - 8) = \pi - \tan^{-1}\left(\frac{1}{2}\right) arg ( z − 8 ) = π − tan − 1 ( 2 1 ) … 31 In a single Argand diagram, sketch the following loci, labelling each locus clearly. ∣ z ∣ = 5 , |z| = 5, ∣ z ∣ = 5 , ∣ z + 8 ∣ = ∣ z − 8 i ∣ . |z + 8| = |z - 8i|. ∣ z + 8∣ = ∣ z − 8 i ∣. Th… 32 On a single Argand diagram sketch the loci given by (a) ∣ z − 12 − 12 e x t i ∣ = 12 |z - 12 - 12 ext{i}| = 12 ∣ z − 12 − 12 e x t i ∣ = 12 , (b) ∣ e x t i z − 1 − 12 e x t i ∣ = 5 | ext{i}z - 1 - 12 ext{i}| = 5 ∣ e x t i z − 1 − 12 e x t i ∣ = 5 … 33 A complex number z varies with t such that z = 2 cos t + i ( 3 sin t ) , where 0 ≤ t < 2 π . z = 2\cos t + i(3\sin t),\quad\text{where } 0 \le t < 2\pi. z = 2 cos t + i ( 3 sin t ) , where 0 ≤ t < 2 π . By taking x = R e ( z ) x = \mathrm{Re}(z) x = Re ( z ) … 34 It is known that w w w satisfies the equation ∣ 2 w − 1 ∣ ≤ ∣ w + 1 ∣ |2w - 1| \le |w + 1| ∣2 w − 1∣ ≤ ∣ w + 1∣ . If w ∈ R w \in \mathbb{R} w ∈ R , find the range of values of w w w … 35 The complex numbers z z z and w w w are such that z = 1 + i a , w = − b − i z = 1 + i a,\quad w = -b - i z = 1 + ia , w = − b − i where a a a and b b b are real and positive. Gi… 36 The complex number w w w has modulus 2 \sqrt{2} 2 and argument 1 4 π \tfrac{1}{4}\pi 4 1 π and the complex number z z z has modulus 2 \sqrt{2} 2 … 37 The complex number z z z satisfies the relations ∣ z − 2 i ∣ < 4 |z - 2\mathrm{i}| < 4 ∣ z − 2 i ∣ < 4 and ∣ z + 4 − 6 i ∣ ≤ ∣ z − 2 i ∣ |z + 4 - 6\mathrm{i}| \le |z - 2\mathrm{i}| ∣ z + 4 − 6 i ∣ ≤ ∣ z − 2 i ∣ … 38 The complex number z z z satisfies the following inequalities: ∣ z ∣ 2 ≤ 4 and − π 6 ≤ arg ( z + 3 − i ) ≤ 0. |z|^2 \le 4 \quad \text{and} \quad -\frac{\pi}{6} \le \arg(z + \sqrt{3} - \mathrm{i}) \le 0. ∣ z ∣ 2 ≤ 4 and − 6 π ≤ arg ( z + 3 − i ) ≤ 0. … 39 In a single Argand diagram, sketch the following loci, labelling each locus clearly. ∣ z ∣ = 5 |z| = 5 ∣ z ∣ = 5 . ∣ z + 8 ∣ = ∣ z − 8 i ∣ |z + 8| = |z - 8i| ∣ z + 8∣ = ∣ z − 8 i ∣ . Th… 40 The sequence of complex numbers { w n } \{w_n\} { w n } are defined as follows w n = [ 1 + ( n − 1 ) i ] [ 1 + ( n + 1 ) i ] ( 1 + n i ) 2 for n ∈ Z + . w_n = \dfrac{[1+(n-1)i][1+(n+1)i]}{(1+ni)^2}\text{ for }n\in\mathbb{Z}^+. w n = ( 1 + ni ) 2 [ 1 + ( n − 1 ) i ] [ 1 + ( n + 1 ) i ] for n ∈ Z + . … 41 A complex number z z z is given by z = r e i π n z = r \mathrm{e}^{\mathrm{i}\frac{\pi}{n}} z = r e i n π , where 0 < r < 1 0 < r < 1 0 < r < 1 and n n n is a positive i…