凯尔经营着一家网球俱乐部。会员中有54名成人和31名儿童。 他的目标是使至少60%的会员是儿童。 列出一个不等式，以求出凯尔仍需招募的最小儿童人数，从而实现他的目标。 答案 ... 名儿童

1. Define the unknown and express the new numbers of children and total members.

Let $x$ be the number of children Kyle still needs to recruit.

New number of children $=31+x$.

New total number of members $=54+31+x=85+x$.

2. Form the inequality representing at least 60% children.

Since at least $60\%$ of the members should be children,
$\frac{31+x}{85+x}\geq \frac{60}{100}.$

3. Solve the inequality and choose the smallest whole number of children.

$\frac{31+x}{85+x}\geq \frac35$
$5(31+x)\geq 3(85+x)$
$155+5x\geq 255+3x$
$2x\geq 100$
$x\geq 50$

So the smallest number of children Kyle still needs to recruit is $50$.