Triangle ABC is such that AB = 16 cm, BC = 63 cm, AC = 65 cm. Do points A, B and C lie on the circumference of a circle? Explain with working. Answer ... ...

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Worked solution

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1. Identify the longest side and test using Pythagoras' theorem

The longest side is AC=65AC=65 cm.

162+632=256+3969=422516^2+63^2=256+3969=4225

652=422565^2=4225

2. Conclude that the triangle is right-angled

Since

162+632=652,16^2+63^2=65^2,

triangle ABCABC is right-angled at BB.

3. Use the right angle to justify that the three points lie on a circle

A right angle is formed in a semicircle, so ACAC can be the diameter of the circle and BB lies on its circumference.

Therefore, AA, BB and CC lie on the circumference of a circle.

Answer

Yes. Since 162+632=65216^2+63^2=65^2, triangle ABCABC is right-angled at BB. Hence AA, BB and CC lie on the circumference of a circle with ACAC as diameter.

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