Solve the simultaneous equations. x4−y2=2\frac{x}{4}-\frac{y}{2}=2 3x=19+4y3x=19+4y You must show your working. Answer x = ... y = ...

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Worked solution

12

1. Clear the fractions in the first equation.

x4−y2=2\frac{x}{4}-\frac{y}{2}=2
Multiply throughout by 44:
x−2y=8x-2y=8

2. Write both equations in comparable linear form.

From 3x=19+4y,3x=19+4y,
subtract 4y4y from both sides:
3x−4y=193x-4y=19
So the equations are
x−2y=8and3x−4y=19.x-2y=8 \quad \text{and} \quad 3x-4y=19.

3. Eliminate $x$ to find $y$.

Multiply x−2y=8x-2y=8 by 33:
3x−6y=243x-6y=24
Subtract 3x−4y=193x-4y=19:

(3x−6y)−(3x−4y)=24−19−2y=5y=−52\begin{aligned} (3x-6y)-(3x-4y)&=24-19\\ -2y&=5\\ y&=-\frac{5}{2} \end{aligned}

4. Substitute $y$ back to find $x$.

Substitute y=−52y=-\dfrac{5}{2} into x−2y=8x-2y=8:
x−2(−52)=8x-2\left(-\frac{5}{2}\right)=8
x+5=8x+5=8
x=3x=3

Answer

x=9x=9, y=12y=\dfrac{1}{2}

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