Solve the inequalities 3x−1<2x+3≤7+5x3x-1<2x+3\le7+5x.

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Worked solution

12

1. Split the compound inequality into two inequalities.

3x−1<2x+3≤7+5x3x-1<2x+3\le 7+5x

This means

3x−1<2x+33x-1<2x+3 and 2x+3≤7+5x2x+3\le 7+5x.

2. Solve the left inequality.

3x−1<2x+33x-1<2x+3

3x−2x<3+13x-2x<3+1

x<4x<4

3. Solve the right inequality and combine both results.

2x+3≤7+5x2x+3\le 7+5x

2x−5x≤7−32x-5x\le 7-3

−3x≤4-3x\le 4

Dividing by −3-3 reverses the inequality sign:

x≥−43x\ge -\dfrac{4}{3}

Combining with x<4x<4,

−43≤x<4-\dfrac{4}{3}\le x<4.

Answer

−43≤x<4-\dfrac{4}{3}\le x<4

AI analysis — may contain mistakes.

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