The roots of the quadratic equation x2−8x+k=0x^2 - 8x + k = 0 are α\alpha and β\beta. Given that α−β=2\alpha - \beta = 2, find the value of the constant kk.

Worked solution

1. 根据二次方程写出两根之和与两根之积

对于一元二次方程 x2−8x+k=0x^2 - 8x + k = 0,由根与系数的关系(韦达定理)可得:
α+β=8\alpha + \beta = 8
αβ=k\alpha \beta = k

2. 联立方程求解两根 $\alpha$ 和 $\beta$ 的值

已知 α−β=2\alpha - \beta = 2,与 α+β=8\alpha + \beta = 8 联立组成方程组:
{α+β=8α−β=2\begin{cases} \alpha + \beta = 8 \\ \alpha - \beta = 2 \end{cases}
两式相加得 2α=10  ⟹  α=52\alpha = 10 \implies \alpha = 5。
两式相减得 2β=6  ⟹  β=32\beta = 6 \implies \beta = 3。

3. 计算常数 $k$ 的值

将 α=5\alpha = 5 和 β=3\beta = 3 代入两根之积的表达式:
k=αβ=5×3=15k = \alpha \beta = 5 \times 3 = 15

Answer

k=15k = 15

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