The roots of the quadratic equation x2−5x+3=0x^2 - 5x + 3 = 0 are α\alpha and β\beta. Without solving the equation, find the exact value of 1α+1β\frac{1}{\alpha} + \frac{1}{\beta}.

Worked solution

1. 利用根与系数的关系写出两根之和与两根之积

对于二次方程 x2−5x+3=0x^2 - 5x + 3 = 0,由根与系数的关系可得:
α+β=−−51=5\alpha + \beta = -\frac{-5}{1} = 5
αβ=31=3\alpha \beta = \frac{3}{1} = 3

2. 将待求代数式通分并代入数值计算

将 1α+1β\frac{1}{\alpha} + \frac{1}{\beta} 通分改写为以 α+β\alpha+\beta 与 αβ\alpha\beta 表示的形式:
1α+1β=α+βαβ\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}
代入 α+β=5\alpha + \beta = 5 和 αβ=3\alpha \beta = 3:
1α+1β=53\frac{1}{\alpha} + \frac{1}{\beta} = \frac{5}{3}

Answer

53\frac{5}{3}(或 1231\frac{2}{3})

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