Solve the inequality 4x+3−2≤5\dfrac{4x+3}{-2} \le 5.

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Worked solution

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1. Remove the denominator and reverse the inequality sign because multiplying by a negative number

4x+3−2≤5\frac{4x+3}{-2} \leq 5
Multiply both sides by −2-2:
4x+3≥−104x+3 \geq -10

2. Solve the resulting linear inequality for $x$

4x+3≥−104x+3 \geq -10
4x≥−134x \geq -13
x≥−134x \geq -\frac{13}{4}

Answer

x≥−134x \geq -\dfrac{13}{4}

AI analysis — may contain mistakes.

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