求 的取值范围,使得对于所有实数 ,恒有 。 已知曲线 ,其中 是常数,求 使 x 轴为该曲线切线的 的可能值。 使该曲线具有正 y 轴截距的 的取值范围。 证明对于所有实数 ,方程 均无实根。
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完整解法
5(a)
1. Rearrange the inequality into standard quadratic form and state the conditions for it to be always negative
For the quadratic expression to be always negative for all real values of , we must have:
- Coefficient of
- Discriminant
2. Set up and simplify the discriminant inequality
Divide by (and flip the inequality sign):
3. Solve the quadratic inequality for $k$
This gives the ranges:
4. Combine the conditions to find the final range of $k$
Since we established earlier that , we must reject .
Taking the intersection of and :
5(b)(i)
1. State the condition for the x-axis to be a tangent to the curve
For the x-axis () to be a tangent to the curve, the equation must have two equal real roots, so the discriminant .
2. Form the equation in terms of $m$
3. Solve the quadratic equation for $m$
or
5(b)(ii)
1. Find the expression for the y-intercept
When ,
2. Set up and solve the inequality for a positive y-intercept
For a positive y-intercept, :
5(c)
1. Formulate the discriminant of the quadratic equation in $x$
For the equation , the discriminant is:
2. Simplify the discriminant and show it is always negative
Since for all real values of , .
Therefore, .
Since for all real , the equation has no real roots.
Since the discriminant is always negative, the equation has no real roots.
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