2020有多少个正整数因子,它们各自的因子个数都大于3?(例如,12有6个因子,即1,2,3,4,6,12。)
A. 6
B. 7
C. 8
D. 9
E. 10

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完整解法

1. 2020 AMC 8 官方解析

The number 2020 has 12 factors.
2020=1⋅20202020 = 1 \cdot 2020
=2⋅1010= 2 \cdot 1010
=4⋅505= 4 \cdot 505
=5⋅404= 5 \cdot 404
=10⋅202= 10 \cdot 202
=20⋅101= 20 \cdot 101

These factors may be classified as follows:
• The number 1 has exactly 1 factor.
• The numbers 2, 5, and 101 are primes, so each has exactly 2 factors.
• The number 4 has exactly 3 factors, namely 1, 2, and 4.
• The remaining 7 numbers, 10, 20, 202, 404, 505, 1010, and 2020, each have more than 3 factors. Thus 7 of the factors of 2020 have more than 3 factors.

2020 有 12 个约数 .
2020=1⋅20202020 = 1 \cdot 2020
=2⋅1010= 2 \cdot 1010
=4⋅505= 4 \cdot 505
=5⋅404= 5 \cdot 404
=10⋅202= 10 \cdot 202
=20⋅101= 20 \cdot 101

这些约数可以按照如下分类:
• 数字1有且只有1个约数 .
• 数字2 , 5和101都是质数,所有每个数都有且只有2个约数 .
• 数字4有且只有3个约数,分别是1 , 2和4 .
• 其余7个数字,10 , 20 , 202 , 404 , 505 , 1010 , 和2020,每个数都有3个以上的约数 .
因此2020的约数中有7个数具有3个以上的约数 .

In order to determine the number of factors of 2020, note that the prime factorization of 2020 is 2020=22⋅51⋅10112020 = 2^2 \cdot 5^1 \cdot 101^1.
This means that each factor of 2020 has the form 2a⋅5b⋅101c2^a \cdot 5^b \cdot 101^c, where a=0,1a = 0, 1, or 22; b=0b = 0 or 11; and c=0c = 0 or 11. Thus the number of factors of 2020 is 3⋅2⋅2=123 \cdot 2 \cdot 2 = 12.
By similar reasoning, any positive integer with at least 2 distinct prime factors, say pp and qq, has at least 4 factors, namely 11, pp, qq, and pqpq.
The factors of 2020 that have no more than 1 distinct prime factor are 1, 2, 4, 5, and 101. Each of these has at most 3 factors. The remaining 7 factors, 10, 20, 202, 404, 505, 1010, and 2020, each have at least 2 distinct prime factors. Therefore 7 of the factors of 2020 have more than 3 factors.

为了确定2020的所有约数的数量,可以将2020进行素因数分解如下
2020=22⋅51⋅10112020 = 2^2 \cdot 5^1 \cdot 101^1
这意味着2020的每个约数都可以表示为2a⋅5b⋅101c2^a \cdot 5^b \cdot 101^c的形式,其中a=0,1a = 0, 1或22;b=0b = 0或11;并且c=0c = 0或11. 因此,2020的约数数量为3⋅2⋅2=123 \cdot 2 \cdot 2 = 12.
类似地,任何具有至少2个不同的素数因子(例如pp和qq)的正整数都具有至少4个约数,即11,pp,qq和pqpq. 2020的约数中具有不超过1个素数因子的是1,2,4,51, 2, 4, 5和101101. 其中每个数最多具有3个约数 . 其余的7个因子,即10,20,202,404,505,101010, 20, 202, 404, 505, 1010和20202020,每个数至少具有2个素数因子 . 因此,在2020的所有约数中有7个数有3个以上的约数 .

答案

B. 7

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