将 1400 表示为其质因数的乘积。 答 ... 由此,解释为什么 1400 不是一个完全平方数。 答 ... ... a 和 b 都是质数。求 a 和 b 的值,使得 1400×ab1400 \times \frac{a}{b} 是一个完全立方数。 答 a = ... b = ...

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完整解法

5(a)

1. Divide 1400 repeatedly by prime numbers until all factors are prime.

1400=14×1001400 = 14 \times 100

=(2×7)(2×2×5×5)= (2 \times 7)(2 \times 2 \times 5 \times 5)

2. Write the prime factors neatly using powers.

1400=2×7×2×2×5×51400 = 2 \times 7 \times 2 \times 2 \times 5 \times 5

=23×52×7= 2^3 \times 5^2 \times 7

答案

1400=23×52×71400 = 2^3 \times 5^2 \times 7

5(b)

1. Use the prime factorisation to check whether all prime powers are even.

From part (a),
1400=23×52×71.1400=2^3\times5^2\times7^1.
For a perfect square, every prime factor must have an even power. Here, 232^3 and 717^1 have odd powers, so 14001400 is not a perfect square.

答案

1400=23×52×71400=2^3\times5^2\times7. Since the powers of 22 and 77 are odd, 14001400 is not a perfect square.

5(c)

1. Use the prime factorisation and identify the exponent changes needed for a perfect cube.

From part (a),
1400=23×52×71.1400=2^3\times5^2\times7^1.
For a perfect cube, each power must be a multiple of 33.

The power of 55 is 22, so multiply by 55 to make it 535^3.

The power of 77 is 11, so divide by 77 to remove the factor 77 completely, giving power 00, which is a multiple of 33.

2. State the prime values of $a$ and $b$ and check the resulting expression is a perfect cube.

Hence
a=5,b=7.a=5,\qquad b=7.
Check:
1400×57=23×52×7×57=23×53=(10)3,1400\times\frac{5}{7}=2^3\times5^2\times7\times\frac{5}{7}=2^3\times5^3=(10)^3,
which is a perfect cube.

答案

a=5,b=7a=5,\quad b=7

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