某数列的前四项分别为 5, 94\dfrac{9}{4}, 139\dfrac{13}{9}, 1716\dfrac{17}{16}。 写出该数列的第五项。 答案 ... 求该数列第 n 项 TnT_n 关于 n 的表达式。 答案 TnT_n = ... 以利亚(Elijah)从 his 桌游中发现了一个数字网格。 图示为该数字网格的一部分。 如图所示,一个圈出四个数字的矩形可以放置在网格的任何位置。 如果用 p 表示该矩形右上角的数字,请写出用 p 表示的该矩形左下角数字的表达式。 答案 ... 证明矩形对角线上两对数字乘积的差始终为 −7。 答案 以利亚说,矩形中四个数字之和不可能为 199。
写出相关的计算过程,证明他是正确的。
答案

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它不会直接告诉你答案,而是问你卡在哪一步看看 AI 是怎么陪你一步步弄懂这道题的

完整解法

3(a)(i)

1. Recognise and extend the numerator and denominator patterns to the fifth term.

The terms are
51, 94, 139, 1716.\frac{5}{1},\ \frac{9}{4},\ \frac{13}{9},\ \frac{17}{16}.
The numerators are 5,9,13,175,9,13,17, increasing by 44, so the next numerator is 2121.

The denominators are 1,4,9,161,4,9,16, which are 12,22,32,421^2,2^2,3^2,4^2, so the next denominator is 52=255^2=25.

Hence the fifth term is
2125.\frac{21}{25}.

答案

2125\dfrac{21}{25}

3(a)(ii)

1. Identify the numerator pattern and write it in terms of $n$.

The numerators are
5,9,13,17,…5, 9, 13, 17, \ldots

They increase by 44 each time, so the numerator of the nnth term is
5+4(n−1)=4n+1.5+4(n-1)=4n+1.

2. Identify the denominator pattern and form the nth term.

The denominators are
1,4,9,16,…1, 4, 9, 16, \ldots

These are square numbers:
12,22,32,42,…1^2, 2^2, 3^2, 4^2, \ldots

So the denominator of the nnth term is n2n^2.

Hence,
Tn=4n+1n2.T_n=\frac{4n+1}{n^2}.

答案

Tn=4n+1n2T_n=\dfrac{4n+1}{n^2}

3(b)(i)

1. Relate the bottom left number to the top right number using the grid movement.

From the top right corner, move down one row: add 77.

Then move left one column: subtract 11.

So the bottom left number is
p+7−1=p+6.p+7-1=p+6.

答案

p+6p+6

3(b)(ii)

1. Express the four corner numbers in terms of $p$.

The top right corner is pp.

Since the top left corner is one less than pp, it is p−1p-1.

Since the bottom left corner is p+6p+6 from part (b)(i), the bottom right corner is p+7p+7.

So the rectangle is

p−1pp+6p+7\begin{matrix} p-1 & p\\ p+6 & p+7 \end{matrix}

2. Find and simplify the difference between the opposite-corner products.

Using one diagonal product minus the other,
p(p+6)−(p−1)(p+7)p(p+6)-(p-1)(p+7)
=p2+6p−(p2+6p−7)=p^2+6p-(p^2+6p-7)
=−7=-7
Therefore, the difference is always −7-7.

答案

Difference between the products of the numbers in the opposite corners
=p(p+6)−(p−1)(p+7)=−7=p(p+6)-(p-1)(p+7)=-7
Hence the difference is always −7-7.

3(b)(iii)

1. Express the four numbers in the rectangle in terms of the top right number.

Let the top right number be pp.

Then the top left number is p−1p-1, the bottom left number is p+6p+6, and the bottom right number is p+7p+7.

So the four numbers are
p−1, p, p+6, p+7.p-1,\, p,\, p+6,\, p+7.

2. Form and simplify the equation for the sum being 199.

If the sum were 199199,
(p−1)+p+(p+6)+(p+7)=199(p-1)+p+(p+6)+(p+7)=199
4p+12=199.4p+12=199.

3. Solve the equation and justify why the result is impossible for the grid.

4p=1874p=187
p=46.75p=46.75

But pp represents a number in the grid, so pp must be an integer. Since 46.7546.75 is not an integer, the sum cannot be 199199.

答案

Let the top right number be pp.

The four numbers are p−1p-1, pp, p+6p+6 and p+7p+7.

p−1+p+p+6+p+7=199p-1+p+p+6+p+7=199
4p+12=1994p+12=199
p=46.75p=46.75

Since pp must be a whole number in the number grid, this is impossible. Hence Elijah is correct.

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