In the diagram, ABCD is a rectangle. Given that AB = (2x+y)(2x + y) cm, BC = (x+y)(x + y) cm, CD = (3x+5y+3)(3x + 5y + 3) cm and AD = (4x+5y−7)(4x + 5y - 7) cm. Find the values of x and y.

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Worked solution

2

1. Use equality of opposite sides in a rectangle to form equations.

In a rectangle, opposite sides are equal.

AB=CDAB = CD:
2x+y=3x+5y+32x + y = 3x + 5y + 3
x+4y=−3(1)x + 4y = -3 \quad \text{(1)}

BC=ADBC = AD:
x+y=4x+5y−7x + y = 4x + 5y - 7
3x+4y=7(2)3x + 4y = 7 \quad \text{(2)}

2. Eliminate one variable to find $x$.

Subtract (1) from (2):
3x+4y−(x+4y)=7−(−3)3x + 4y - (x + 4y) = 7 - (-3)
2x=102x = 10
x=5x = 5

3. Substitute $x$ back into one equation to find $y$.

Substitute x=5x = 5 into (1):
5+4y=−35 + 4y = -3
4y=−84y = -8
y=−2y = -2

Answer

x=6, y=−3x = 6,\ y = -3

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