The diagram shows a sketch of the graph of $y = -10 + 2x$. The line crosses the axes at P and Q.

1. Find the y-intercept P by setting $x=0$.

At P, the line crosses the y-axis, so $x=0$.

$y=-10+2(0)=-10$

Hence, P is $(0,-10)$.

2. Find the x-intercept Q by setting $y=0$.

At Q, the line crosses the x-axis, so $y=0$.

$0=-10+2x$

$2x=10$

$x=5$

Hence, Q is $(5,0)$.

1. Substitute the coordinates of P and Q into the distance formula.

P$(0,-10)$ and Q$(5,0)$

$PQ=\sqrt{(5-0)^2+(0-(-10))^2}$

2. Evaluate and simplify the length.

$PQ=\sqrt{5^2+10^2}$
$=\sqrt{25+100}$
$=\sqrt{125}=5\sqrt{5}$