In the diagram below, ABCD is a parallelogram. CFE and DGE are straight lines. Find $\angle\text{BCF}$. Ans : ___ $^\circ$

1. Find the interior angle $\angle\text{ABC}$ of the parallelogram.

Since $ABCD$ is a parallelogram, $AD \parallel BC$. Therefore, the consecutive interior angles sum to $180^\circ$.
$\angle\text{ABC} = 180^\circ - \angle\text{DAB} = 180^\circ - 112^\circ = 68^\circ$

2. Find $\angle\text{BFC}$ using vertically opposite angles.

The line $AB$ and the line $CFE$ intersect at $F$. Thus, $\angle\text{BFC}$ and $\angle\text{AFE}$ are vertically opposite angles.
$\angle\text{BFC} = \angle\text{AFE} = 95^\circ$

3. Find $\angle\text{BCF}$ using the angle sum of $\triangle\text{BFC}$.

In $\triangle\text{BFC}$, the sum of angles is $180^\circ$.
$\angle\text{BCF} = 180^\circ - \angle\text{BFC} - \angle\text{FBC}$
$\angle\text{BCF} = 180^\circ - 95^\circ - 68^\circ = 17^\circ$