Simplify (a16b−6)32\left(\frac{a^{16}}{b^{-6}}\right)^{\frac{3}{2}}. Answer ...

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Worked solution

8

1. Rewrite the expression inside the brackets using the negative index law.

a16b−6=a16b6\frac{a^{16}}{b^{-6}}=a^{16}b^6
So
(a16b−6)32=(a16b6)32.\left(\frac{a^{16}}{b^{-6}}\right)^{\frac32}=\left(a^{16}b^6\right)^{\frac32}.

2. Raise each factor to the power $\frac32$ and multiply the indices.

(a16b6)32=a16×32b6×32\left(a^{16}b^6\right)^{\frac32}=a^{16\times\frac32}b^{6\times\frac32}
=a24b9=a^{24}b^9

Answer

a24b9a^{24}b^9

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