The roots of the quadratic equation 3x2−5x−1=03x^2 - 5x - 1 = 0 are α\alpha and β\beta. Without solving the equation, find the exact value of α2+β2\alpha^2 + \beta^2.

Worked solution

1. 由韦达定理求出两根之和与两根之积

对于二次方程 3x2−5x−1=03x^2 - 5x - 1 = 0,根据根与系数的关系(韦达定理):
α+β=−−53=53\alpha + \beta = -\frac{-5}{3} = \frac{5}{3}
αβ=−13=−13\alpha\beta = \frac{-1}{3} = -\frac{1}{3}

2. 变形代数式并代入求出 $\alpha^2 + \beta^2$ 的精确值

将 α2+β2\alpha^2 + \beta^2 用 α+β\alpha + \beta 和 αβ\alpha\beta 表示:
α2+β2=(α+β)2−2αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta
代入上述结果:
α2+β2=(53)2−2(−13)=259+23=319\alpha^2 + \beta^2 = \left(\frac{5}{3}\right)^2 - 2\left(-\frac{1}{3}\right) = \frac{25}{9} + \frac{2}{3} = \frac{31}{9}

Answer

319\dfrac{31}{9}

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