等差数列的首项为 aa,公差为 dd,其中 d≠0d \ne 0。 该等差数列的首项、第 5 项和第 15 项是一个等比数列的前三项。

  1. (i)

    用 aa 和 dd 写出该等差数列第 5 项和第 15 项的表达式。

  2. (ii)

    证明 3a=8d3a = 8d。

  3. (iii)

    求该等比数列的公比。

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完整解法

Q3(i)

1. Write down the expression for the 5th term

u5=a+(5−1)d=a+4du_5 = a + (5 - 1)d = a + 4d

2. Write down the expression for the 15th term

u15=a+(15−1)d=a+14du_{15} = a + (15 - 1)d = a + 14d

答案

5th term = a+4da + 4d
15th term = a+14da + 14d

Q3(ii)

1. Set up an equation using the common ratio property of a geometric progression.

a+4da=a+14da+4d\frac{a + 4d}{a} = \frac{a + 14d}{a + 4d}

2. Cross-multiply and expand the equation.

(a+4d)2=a(a+14d)(a + 4d)^2 = a(a + 14d)
a2+8ad+16d2=a2+14ada^2 + 8ad + 16d^2 = a^2 + 14ad

3. Simplify the equation to arrive at the given result, noting that $d \neq 0$.

16d2=6ad16d^2 = 6ad
16d2−6ad=016d^2 - 6ad = 0
2d(8d−3a)=02d(8d - 3a) = 0
Since it is given that d≠0d \ne 0,
8d−3a=08d - 3a = 0
3a=8d3a = 8d (shown)

答案

As shown in the working.

Q3(iii)

1. Express the common ratio in terms of $a$ and $d$.

The common ratio rr is the ratio of the second term to the first term of the geometric progression. Using the terms from part (i):
r=a+4dar = \frac{a + 4d}{a}

2. Substitute the relationship $3a = 8d$ to evaluate the common ratio.

From part (ii), we know that 3a=8d3a = 8d, which gives d=38ad = \frac{3}{8}a.
Substitute this into the expression for rr:
r=a+4(38a)ar = \frac{a + 4\left(\frac{3}{8}a\right)}{a}
r=a+1.5aar = \frac{a + 1.5a}{a}
r=2.5aar = \frac{2.5a}{a}
Since d≠0d \ne 0, a≠0a \ne 0, so we can divide by aa:
r=2.5r = 2.5

答案

2.52.5 or 52\frac{5}{2}

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