Hamid 贷款买车，贷款期限为 3 年，年单利利率为 3.5%。 如果 Hamid 支付的总利息为 $10 374，求他贷款的金额。 答案 $ ... 下表显示了 Hamid 收集的关于他在 2023 年驾驶情况的信息。

描述	数值
2023 年总行驶里程	16 992 km
汽油平均价格	每升 $2.72
他的汽车平均油耗	每 100 km 消耗 6.7 升

计算 Hamid 在 2023 年支付的购油总费用。 答案 $ ... 2020 年初，Hamid 以 $120 500 的现金价格买下了他的车。 每年汽车的价值都会比年初减少其价值的 5%。 在 2023 年底，Hamid 决定卖掉他的车。 解释为什么三年末的减少百分比不是 $120 500 的 15%。 计算他的汽车在 2023 年底的价值。将你的答案精确到最接近的元。 答案 $ ...

1. Write the simple interest equation using the given rate and time.

Simple interest:
$I=Prt$
Given $I=10374$, $r=3.5\%=0.035$ and $t=3$,
$10374=P(0.035)(3)$

2. Solve for the sum borrowed.

$P=\frac{10374}{0.035\times 3}$
$P=98800$

1. Calculate the total amount of petrol used in litres.

Petrol used
$= \frac{16\,992}{100}\times 6.7$
$= 1138.464\text{ litres}$

2. Multiply the litres used by the price per litre.

Total cost
$=1138.464\times 2.72$
$=3099.82208$
To the nearest cent, this is $\char36{}3099.82$.

1. State why the three yearly percentage decreases cannot be added as 15% of the original price.

Each year, the car loses $5\%$ of its value at the start of that year. After the first year, the value is already less than $120 500, so the next $5\%$ is calculated on a smaller amount, not on $120 500.

1. Identify the multiplier for a 5% yearly decrease and the number of years of depreciation.

A decrease of $5\%$ means the car keeps
$100\%-5\%=95\%=0.95$
of its value each year.

From the start of 2020 to the end of 2023, there are $4$ yearly decreases.

2. Apply the repeated percentage decrease to the original car price.

Value at the end of 2023
$=120500(0.95)^4$
$=98119.25625$

3. Round the value to the nearest dollar.

$98119.25625\approx 98119$
correct to the nearest dollar.