Simplify (2p35q)−2×4p−7q−4\left(\dfrac{2p^3}{5q}\right)^{-2}\times\dfrac{4}{p^{-7}q^{-4}}, leaving your answer in positive indices. Ans: ___

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Worked solution

7

1. Apply the negative index to the fraction and simplify the second fraction with negative indices.

(2p35q)−2=(5q2p3)2=25q24p6\left(\frac{2p^3}{5q}\right)^{-2}=\left(\frac{5q}{2p^3}\right)^2=\frac{25q^2}{4p^6}

4p−7q−4=4p7q4\frac{4}{p^{-7}q^{-4}}=4p^7q^4

2. Multiply the simplified expressions and combine like bases.

25q24p6×4p7q4\frac{25q^2}{4p^6}\times 4p^7q^4

=25p7−6q2+4=25p^{7-6}q^{2+4}

=25pq6=25pq^6

Answer

25pq625p q^6

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