ξ={x:x is an integer and −3≤x<7}\xi = \{x : x \text{ is an integer and } -3 \le x < 7\} P={x:−3<x<3}P = \{x : -3 < x < 3\} Q={x:0<x≤3}Q = \{x : 0 < x \le 3\}

  1. ((a))

    Draw a Venn diagram below to illustrate this information.

  2. ((b))

    List the elements in

    1. ((i))

      P′P',

      Answer ...

    2. ((ii))

      P∩QP \cap Q.

      Answer ...

  3. ((c))

    Write down n(P′∪Q)n(P'\cup Q)

    Answer ...

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Worked solution

20((a))

1. List the elements of the universal set and the two subsets.

Since xx is an integer and −3≤x<7-3 \le x < 7,
ξ={−3,−2,−1,0,1,2,3,4,5,6}.\xi=\{-3,-2,-1,0,1,2,3,4,5,6\}.

For PP, −3<x<3-3<x<3, so
P={−2,−1,0,1,2}.P=\{-2,-1,0,1,2\}.

For QQ, 0<x≤30<x\le3, so
Q={1,2,3}.Q=\{1,2,3\}.

2. Identify the elements in each Venn diagram region.

The common elements are
P∩Q={1,2}.P\cap Q=\{1,2\}.

So the regions are:
P only={−2,−1,0},P\text{ only}=\{-2,-1,0\},
Q only={3},Q\text{ only}=\{3\},
ξ outside both P and Q={−3,4,5,6}.\xi\text{ outside both }P\text{ and }Q=\{-3,4,5,6\}.

3. Draw and label the Venn diagram accurately.

Draw a rectangle labelled ξ\xi containing two overlapping circles labelled PP and QQ.

Place:

  • 1,21,2 in the overlap,
  • −2,−1,0-2,-1,0 in PP only,
  • 33 in QQ only,
  • −3,4,5,6-3,4,5,6 outside both circles but inside ξ\xi.
Answer

Draw two overlapping circles labelled PP and QQ inside the rectangle labelled ξ\xi.

  • In P∩QP \cap Q: 1,21, 2
  • In PP only: −2,−1,0-2, -1, 0
  • In QQ only: 33
  • Outside both circles but inside ξ\xi: −3,4,5,6-3, 4, 5, 6

20((b))((i))

1. List the elements in the universal set and remove the elements of $P$.

ξ={−3,−2,−1,0,1,2,3,4,5,6}\xi = \{-3,-2,-1,0,1,2,3,4,5,6\}

P={−2,−1,0,1,2}P = \{-2,-1,0,1,2\}

So the elements not in PP are

P′={−3,3,4,5,6}P' = \{-3,3,4,5,6\}.

Answer

P′={−3,3,4,5,6}P' = \{-3, 3, 4, 5, 6\}

20((b))((ii))

1. Find the common elements of $P$ and $Q$.

From the earlier listing,

P={−2,−1,0,1,2}P = \{-2,-1,0,1,2\} and Q={1,2,3}Q = \{1,2,3\}.

The elements in both sets are 11 and 22.

So, P∩Q={1,2}P \cap Q = \{1,2\}.

Answer

P∩Q={1,2}P \cap Q = \{1, 2\}

20((c))

1. Find the union of $P'$ and $Q$, then count its elements.

From earlier parts,

P′={−3,3,4,5,6}P'=\{-3,3,4,5,6\} and Q={1,2,3}Q=\{1,2,3\}.

So

P′∪Q={−3,1,2,3,4,5,6}P'\cup Q=\{-3,1,2,3,4,5,6\}.

Hence

n(P′∪Q)=6n(P'\cup Q)=6.

Answer

n(P′∪Q)=6n(P'\cup Q)=6

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