ξ={integers x:2<x≤12}\xi = \{\text{integers } x: 2 < x \le 12\} A={prime numbers}A = \{\text{prime numbers}\} B={factors of 12}B = \{\text{factors of 12}\} C={greater than 100}C = \{\text{greater than } \sqrt{100}\} List the elements in A∩C′A \cap C' , Answer ... A∪BA \cup B . Answer ... It is given that M∩N=∅M \cap N = \emptyset and L⊂NL \subset N. Complete and label the Venn diagram below for the sets L, M and N.

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Worked solution

7((a))(i)

1. Identify the relevant sets within the universal set

The universal set is
ξ={3,4,5,6,7,8,9,10,11,12}\xi=\{3,4,5,6,7,8,9,10,11,12\}.

A={prime numbers in ξ}={3,5,7,11}A=\{\text{prime numbers in }\xi\}=\{3,5,7,11\}.

C={numbers in ξ greater than 100}C=\{\text{numbers in }\xi\text{ greater than }\sqrt{100}\}.
Since 100=10\sqrt{100}=10,
C={11,12}C=\{11,12\}.

2. Find the complement of $C$ and intersect it with $A$

C′={3,4,5,6,7,8,9,10}C'=\{3,4,5,6,7,8,9,10\}.

So
A∩C′={3,5,7,11}∩{3,4,5,6,7,8,9,10}={3,5,7}.A\cap C'=\{3,5,7,11\}\cap\{3,4,5,6,7,8,9,10\}=\{3,5,7\}.

Answer

{3,5,7}\{3,5,7\}

7((a))(ii)

1. List the elements of $A$ and $B$ within the universal set

The universal set is ξ={3,4,5,6,7,8,9,10,11,12}\xi=\{3,4,5,6,7,8,9,10,11,12\}.

Prime numbers in ξ\xi:
A={3,5,7,11}A=\{3,5,7,11\}

Factors of 1212 in ξ\xi:
B={3,4,6,12}B=\{3,4,6,12\}

2. Find the union of $A$ and $B$

A∪BA\cup B contains all elements that are in AA or in BB.

A∪B={3,4,5,6,7,11,12}A\cup B=\{3,4,5,6,7,11,12\}

Answer

{3,4,5,6,7,11,12}\{3,4,5,6,7,11,12\}

7((b))

1. Represent $M \cap N = \emptyset$ on the Venn diagram

M∩N=∅M \cap N = \emptyset means that MM and NN have no common elements.

So draw the circles for MM and NN separately, with no overlap.

2. Represent $L \subset N$ on the Venn diagram

L⊂NL \subset N means every element of LL is also in NN.

So draw the circle for LL completely inside the circle for NN, and label all three circles LL, MM and NN.

Answer

Draw a rectangle for the universal set. Inside it, draw two non-overlapping circles labelled MM and NN. Draw a smaller circle labelled LL completely inside the circle NN.

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