A curve is such that d2ydx2=12(3−2x)2\frac{\text{d}^2y}{\text{d}x^2} = \frac{12}{(3-2x)^2}. Given that the curve passes through the points (12,1)\left(\frac{1}{2}, 1\right) and (1,ln⁡(8e2))\left(1, \ln(8e^2)\right), show that the yy-intercept of the curve can be expressed as aln⁡(bc)a \ln\left(\frac{b}{c}\right) where aa, bb and cc are constants.

Integration reverseIntegration linear argumentFunctions and graphsSimultaneous one linear中文
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