Expand and simplify 2x−3(2x−5).2x-3(2x-5). Answer ___ Factorise completely x2−y2−2x+2yx^{2}-y^{2}-2x+2y. Answer ___

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Worked solution

1(a)

1. Expand the bracket and simplify like terms

2x−3(2x−5)=2x−6x+15=−4x+152x-3(2x-5)=2x-6x+15=-4x+15

Answer

−4x+15-4x+15

1(b)

1. Group the expression to create common factors

x2−y2−2x+2y=(x2−y2)−2(x−y)x^{2}-y^{2}-2x+2y=(x^{2}-y^{2})-2(x-y)

2. Factorise completely by extracting the common factor

$(x^{2}-y^{2})-2(x-y)=(x-y)(x+y)-2(x-y)

=(x−y)(x+y−2)=(x-y)(x+y-2)

Answer

(x−y)(x+y−2)(x-y)(x+y-2)

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