A curve has the equation y=2sin⁡3x2cos⁡3x+5y = \frac{2 \sin 3x}{2 \cos 3x + 5}.

  1. (i)

    Find the value of aa and of bb for which dydx=a+bcos⁡3x(2cos⁡3x+5)2\frac{\text{d}y}{\text{d}x} = \frac{a + b \cos 3x}{(2 \cos 3x + 5)^2}.

  2. (ii)

    Hence, find the xx-coordinates, where 0≤x≤π0 \le x \le \pi, of the points at which the normal to the curve is parallel to the yy-axis.

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