计算 $(1)10-(-16)+(-5)-17(2)-36\times(-\dfrac{5}{6})+\dfrac{3}{5}\div(-0.2)(3)(\dfrac{9}{10}-\dfrac{1}{15}+\dfrac{1}{6})\div(-\dfrac{1}{30})(4)\left|-\dfrac{7}{9}\right|\div(\dfrac{2}{3}-\dfrac{1}{5})\times{{(-4)}^{2}}$

1. 去掉括号并化简符号

$10-(-16)+(-5)-17 = 10+16-5-17$

2. 计算加减法混合运算得出结果

$10+16-5-17 = 26-5-17 = 21-17 = 4$

1. 计算乘法项

$-36\times(-\dfrac{5}{6}) = 36 \times \dfrac{5}{6} = 30$

2. 将小数化为分数并计算除法项

$\dfrac{3}{5}\div(-0.2) = \dfrac{3}{5}\div(-\dfrac{1}{5}) = \dfrac{3}{5}\times(-5) = -3$

3. 将两部分结果相加

$30 + (-3) = 27$

1. 将除法转化为乘法，并应用乘法分配律展开

$(\dfrac{9}{10}-\dfrac{1}{15}+\dfrac{1}{6})\div(-\dfrac{1}{30}) = (\dfrac{9}{10}-\dfrac{1}{15}+\dfrac{1}{6})\times(-30) = \dfrac{9}{10}\times(-30) - \dfrac{1}{15}\times(-30) + \dfrac{1}{6}\times(-30)$

2. 分别计算每一项的乘积

$\dfrac{9}{10}\times(-30) = -27$, $- \dfrac{1}{15}\times(-30) = +2$, $\dfrac{1}{6}\times(-30) = -5$

3. 对结果进行加减求和

$-27 + 2 - 5 = -30$

1. 化简绝对值和乘方部分

$\left|-\dfrac{7}{9}\right| = \dfrac{7}{9}$, $(-4)^2 = 16$
原式可化为：$\dfrac{7}{9}\div(\dfrac{2}{3}-\dfrac{1}{5})\times 16$

2. 计算小括号内的通分减法

$\dfrac{2}{3}-\dfrac{1}{5} = \dfrac{10}{15}-\dfrac{3}{15} = \dfrac{7}{15}$
原式变为：$\dfrac{7}{9}\div\dfrac{7}{15}\times 16$

3. 进行有理数的乘除混合运算得出最终答案

$\dfrac{7}{9}\div\dfrac{7}{15}\times 16 = \dfrac{7}{9}\times\dfrac{15}{7}\times 16 = \dfrac{5}{3}\times 16 = \dfrac{80}{3}$