Simplify the following expressions, leaving your answers in positive index.

  1. (a)

    (−a2)3÷4b0(-a^2)^3 \div 4b^0

    Answer ...

  2. (b)

    (a−1b)2×(b)3(a^{-1}b)^2 \times (\sqrt{b})^3

    Answer ...

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Worked solution

1(a)

1. Simplify the power of the bracket and the zero index term.

(−a2)3=(−1)3(a2)3=−a6(-a^2)^3 = (-1)^3(a^2)^3 = -a^6

b0=1b^0=1, so 4b0=44b^0=4.

2. Divide the simplified terms and write the answer with positive indices.

(−a2)3÷4b0=−a6÷4=−a64(-a^2)^3 \div 4b^0 = -a^6 \div 4 = -\frac{a^6}{4}

Answer

−a64-\dfrac{a^6}{4}

1(b)

1. Expand the power of the first bracket using index laws.

(a−1b)2=(a−1)2b2=a−2b2(a^{-1}b)^2=(a^{-1})^2b^2=a^{-2}b^2

2. Rewrite the square root as a fractional index and combine powers of $b$, leaving positive indices.

(b)3=(b12)3=b32(\sqrt{b})^3=(b^{\frac12})^3=b^{\frac32}

a−2b2×b32=a−2b2+32=a−2b72=b72a2a^{-2}b^2\times b^{\frac32}=a^{-2}b^{2+\frac32}=a^{-2}b^{\frac72}=\frac{b^{\frac72}}{a^2}

Answer

b72a2\dfrac{b^{\frac{7}{2}}}{a^2}

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