一个木块的质量为 115 克，精确到最接近的克。
木块的体积为 6 cm^3，精确到最接近的 cm^3。
求该木块可能的最大密度，以 g/cm^3 为单位。 $\text{密度} = \dfrac{\text{质量}}{\text{体积}}$ 答案 ... g/cm^3

1. Find the upper bound of the mass and the lower bound of the volume.

Mass is $115$ g correct to the nearest gram, so
$114.5 \leq m < 115.5.$
Volume is $6$ cm$^3$ correct to the nearest cm$^3$, so
$5.5 \leq V < 6.5.$
For the largest density, use $m=115.5$ and $V=5.5$.

2. Calculate the largest possible density.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$
$\text{Largest possible density}=\frac{115.5}{5.5}=21.$