AA 和 BB 是锐角,且满足 sin⁡(A−B)=14\sin(A - B) = \frac{1}{4} 以及 sin⁡Acos⁡B=35\sin A \cos B = \frac{3}{5}。 在不使用计算器的情况下,求以下各项的值:

  1. (i)

    cos⁡Asin⁡B\cos A \sin B控制,

  2. (ii)

    sin⁡(A+B)\sin(A + B),

  3. (iii)

    2tan⁡Acot⁡B2 \tan A \cot B。

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完整解法

4(i)

1. Apply the compound angle formula for $\sin(A - B)$

sin⁡(A−B)=sin⁡Acos⁡B−cos⁡Asin⁡B\sin(A - B) = \sin A \cos B - \cos A \sin B

2. Substitute the given values and solve for $\cos A \sin B$

14=35−cos⁡Asin⁡B\frac{1}{4} = \frac{3}{5} - \cos A \sin B

cos⁡Asin⁡B=35−14\cos A \sin B = \frac{3}{5} - \frac{1}{4}

cos⁡Asin⁡B=1220−520=720\cos A \sin B = \frac{12}{20} - \frac{5}{20} = \frac{7}{20}

答案

720\frac{7}{20}

4(ii)

1. Find the value of $\cos A \sin B$ from the given information (result of part i)

sin⁡(A−B)=sin⁡Acos⁡B−cos⁡Asin⁡B\sin(A - B) = \sin A \cos B - \cos A \sin B
14=35−cos⁡Asin⁡B\frac{1}{4} = \frac{3}{5} - \cos A \sin B
cos⁡Asin⁡B=35−14=720\cos A \sin B = \frac{3}{5} - \frac{1}{4} = \frac{7}{20}

2. Use the addition formula for sine to find $\sin(A + B)$

sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B\sin(A + B) = \sin A \cos B + \cos A \sin B
sin⁡(A+B)=35+720\sin(A + B) = \frac{3}{5} + \frac{7}{20}
sin⁡(A+B)=1220+720=1920\sin(A + B) = \frac{12}{20} + \frac{7}{20} = \frac{19}{20}

答案

1920\frac{19}{20}

4(iii)

1. Express the given expression in terms of sine and cosine

2tan⁡Acot⁡B=2(sin⁡Acos⁡A)(cos⁡Bsin⁡B)=2(sin⁡Acos⁡Bcos⁡Asin⁡B)2 \tan A \cot B = 2 \left( \frac{\sin A}{\cos A} \right) \left( \frac{\cos B}{\sin B} \right) = 2 \left( \frac{\sin A \cos B}{\cos A \sin B} \right)

2. Substitute known values to evaluate the expression

From part (i), we found cos⁡Asin⁡B=720\cos A \sin B = \frac{7}{20}. We are given sin⁡Acos⁡B=35\sin A \cos B = \frac{3}{5}.

2(sin⁡Acos⁡Bcos⁡Asin⁡B)=2(35720)2 \left( \frac{\sin A \cos B}{\cos A \sin B} \right) = 2 \left( \frac{\frac{3}{5}}{\frac{7}{20}} \right)
=2(35×207)= 2 \left( \frac{3}{5} \times \frac{20}{7} \right)
=2(127)=247= 2 \left( \frac{12}{7} \right) = \frac{24}{7}

答案

247\frac{24}{7}

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