1. Apply the double angle identity for sine
2(2sinxcosx)+3cosx=0
4sinxcosx+3cosx=0
2. Factorise the equation to find the possible trigonometric values
cosx(4sinx+3)=0
cosx=0orsinx=−43
3. Calculate the principal values for each case
For cosx=0, the principal value is:
x=cos−1(0)=90∘
For sinx=−0.75, the principal value is:
x=sin−1(−0.75)=−48.590∘≈−48.6∘ (to 1 d.p.)
答案90∘,−48.6∘