Calculate, in degrees, the principal values of xx which satisfy
2sin⁡2x+3cos⁡x=02 \sin 2x + 3 \cos x = 0 .

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Worked solution

10(a)

1. Apply the double angle identity for sine

2(2sin⁡xcos⁡x)+3cos⁡x=02(2 \sin x \cos x) + 3 \cos x = 0
4sin⁡xcos⁡x+3cos⁡x=04 \sin x \cos x + 3 \cos x = 0

2. Factorise the equation to find the possible trigonometric values

cos⁡x(4sin⁡x+3)=0\cos x (4 \sin x + 3) = 0
cos⁡x=0orsin⁡x=−34\cos x = 0 \quad \text{or} \quad \sin x = -\frac{3}{4}

3. Calculate the principal values for each case

For cos⁡x=0\cos x = 0, the principal value is:
x=cos⁡−1(0)=90∘x = \cos^{-1}(0) = 90^\circ

For sin⁡x=−0.75\sin x = -0.75, the principal value is:
x=sin⁡−1(−0.75)=−48.590∘≈−48.6∘ (to 1 d.p.)x = \sin^{-1}(-0.75) = -48.590^\circ \approx -48.6^\circ \text{ (to 1 d.p.)}

Answer

90∘,−48.6∘90^\circ, -48.6^\circ

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