y 与 x 的平方成反比,x>0x > 0。

  1. (a)

    如果 x 增加了 25%,求 y 的百分比变化。

    答案 ...%

  2. (b)

    已知当 y=16y = 16 时 x=12x = \frac{1}{2},求

    1. (i)

      求连接 y 和 x 的方程。

      答案 ...

    2. (ii)

      求当 y=100y = 100 时 x 的值。

      答案 x = ...

  3. (c)

    画出表示 y 和 x 之间关系的图像。

先不看答案,让 AI 诊断你卡在哪里?

它不会直接告诉你答案,而是问你卡在哪一步看看 AI 是怎么陪你一步步弄懂这道题的

完整解法

17(a)

1. Express the new value of $x$ after a $25\%$ increase and relate it to $y$.

If xx is increased by 25%25\%, then
xnew=1.25x=54x.x_{\text{new}}=1.25x=\frac{5}{4}x.
Since yy is inversely proportional to the square of xx,
y∝1x2.y \propto \frac{1}{x^2}.

2. Find the percentage change in $y$.

So
ynewyold=1(54)2=12516=1625=0.64.\frac{y_{\text{new}}}{y_{\text{old}}}=\frac{1}{\left(\frac{5}{4}\right)^2}=\frac{1}{\frac{25}{16}}=\frac{16}{25}=0.64.
Thus the new value of yy is 64%64\% of the old value.

Percentage change in yy:
64%−100%=−36%.64\%-100\%=-36\%.
So yy decreases by 36%36\%.

答案

36%36\% decrease

17(b)(i)

1. Write the inverse proportion relation using a constant of proportionality.

Since yy is inversely proportional to the square of xx,
y=kx2y=\frac{k}{x^2}
where kk is a constant.

2. Substitute the given values to find the constant and state the equation.

Given y=16y=16 when x=12x=\frac12,
16=k(12)216=\frac{k}{\left(\frac12\right)^2}
16=k14=4k16=\frac{k}{\frac14}=4k
k=4k=4
Hence,
y=4x2.y=\frac{4}{x^2}.

答案

y=4x2y=\dfrac{4}{x^2}

17(b)(ii)

1. Substitute $y=100$ into the equation connecting $y$ and $x$.

From part (b)(i),
y=4x2.y=\frac{4}{x^2}.
When y=100y=100,
100=4x2.100=\frac{4}{x^2}.

2. Solve the equation for $x$, using $x>0$.

100x2=4100x^2=4
x2=4100=125x^2=\frac{4}{100}=\frac{1}{25}
Since x>0x>0,
x=15.x=\frac{1}{5}.

答案

x=15x=\dfrac{1}{5}

17(c)

1. Identify the equation and the permitted region of the graph.

From part (b)(i),
y=4x2.y=\frac{4}{x^2}.
Since x>0x>0 and 4x2>0\frac{4}{x^2}>0, the graph lies only in the first quadrant.

2. Sketch the shape and asymptotic behaviour of the curve.

Sketch a smooth decreasing curve for x>0x>0:

  • as x→0+x\to 0^+, y→∞y\to \infty, so the curve approaches the yy-axis but does not touch it;
  • as x→∞x\to \infty, y→0y\to 0, so the curve approaches the xx-axis but does not touch it.

The curve should be in the first quadrant only.

答案

A decreasing curve in the first quadrant only, representing y=4x2y=\dfrac{4}{x^2} for x>0x>0, approaching the yy-axis as x→0+x\to 0^+ and approaching the xx-axis as x→∞x\to \infty.

AI 分析,可能出错

用 AI 批改,圈出写错的那一步,并自动将你的薄弱点存入错题本,形成你的错因库。

同一知识点的其他题

  1. 1一根长为 50 cm 的木头形状为均匀圆柱体。从该木头中切出一个棱柱,使其横截面为圆的一个劣弓形,圆心为 O,半径为 r cm,且 ∠AOB=79π\angle AOB = \frac{7}{9}\pi 弧度。 已知该劣弓形的面积为 3×10−3 m23 \times 10^{-3}\ \mathrm{m}^2…
  2. 2已知 y=xsin⁡x+cos⁡2(x2)y = x\sin x + \cos^2\left(\tfrac{x}{2}\right)。 求 dydx\dfrac{dy}{dx} 的表达式,将其表示为 (xcos⁡x+psin⁡x)(x\cos x + p\sin x) 的形式,其中 pp 为常数。…
  3. 3y=x34−2x+3y = \dfrac{x^3}{4} - 2x + 3。 完成 y=x34−2x+3y = \dfrac{x^3}{4} - 2x + 3 的数值表。 在对面的网格中,画出 −4≤x≤4-4 \le x \le 4 时 y=x34−2x+3y = \dfrac{x^3}{4} - 2x + 3…
  4. 4老麦克唐纳有一个周围有石墙的农场。该图显示了他计划建造两个围栏的一部分农场区域。 篱笆的总长度为 180 m。 证明 y=90−32xy = 90 - \frac{3}{2}x。 A 是 2 个围栏的总面积。 构建一个关于 x 且以 A 为因变量的二次…
  5. 5已知 f′′(x)=e−12x+5(5x−9)2f''(x) = e^{-\tfrac{1}{2}x} + \dfrac{5}{(5x-9)^2}。 已知 x 轴是曲线 y=f(x)y = f(x) 在 x=2x = 2 处的切线, 求 f′(x)f'(x) 的表达式。 由此求 f(x)f(x)…