Cheryl had three more 50\cent coins than $1 coins at first. She paid$2.50 for a pen using 3 coins. Each statement is either true, false or not possible to tell from the information given. Put a tick (\u2713) to indicate your answer.

1. Determine the combination of 3 coins used to pay $2.50

To make $\char36{}2.50$ using exactly 3 coins (which can only be $\char36{}1$ or $50\cent$ coins):
$2 \times \char36{}1 + 1 \times 50\cent = \char36{}2.50$
So Cheryl used two $\char36{}1$ coins and one $50\cent$ coin.

2. Calculate the new difference between the number of 50¢ coins and $1 coins

Let the initial number of $\char36{}1$ coins be $x$.
Initial number of $50\cent$ coins = $x + 3$.
After paying, she has $(x - 2)$ $\char36{}1$ coins and $(x + 3 - 1) = (x + 2)$ $50\cent$ coins.
Difference = $(x + 2) - (x - 2) = 4$.
Thus, she has four more $50\cent$ coins than $\char36{}1$ coins.