A group of singers are arranged in 5 rows. There are 7 singers in the second row. Each row has nn more singers than the row in front of it.

  1. (a)

    How many singers are there in the first row? Leave your answer in terms of nn.

    Ans : (a) ___

  2. (b)

    Given that there are 13 singers in the fourth row, find the value of nn.

    Ans : (b) ___

  3. (c)

    How many singers are there altogether in the 5 rows?

    Ans : (c) ___

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Worked solution

8(a)

1. Express the number of singers in the first row in terms of $n$

Since each row has nn more singers than the row in front of it, the first row has nn fewer singers than the second row.
Number of singers in the first row = 7−n7 - n

Answer

7−n7 - n

8(b)

1. Express the number of singers in the fourth row in terms of $n$

Since the second row has 77 singers, the third row has 7+n7 + n singers, and the fourth row has 7+2n7 + 2n singers.

2. Form an equation and solve for $n$

7+2n=137 + 2n = 13
2n=13−72n = 13 - 7
2n=62n = 6
n=3n = 3

Answer

33

8(c)

1. Determine the number of singers in each of the 5 rows

From parts (a) and (b), the first row has 44 singers and the common difference is n=3n = 3.
The number of singers in the 5 rows are: 4,7,10,13,164, 7, 10, 13, 16.

2. Calculate the total number of singers

Total=4+7+10+13+16=50\text{Total} = 4 + 7 + 10 + 13 + 16 = 50

Answer

5050

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