Three parts of a circle with a radius of 14 cm is shaded. These three parts add up to a quarter of the circle. What is the total perimeter of the three shaded parts? Take π=227\pi = \frac{22}{7}

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Worked solution

14

1. Calculate the total arc length of the three shaded parts

The three parts add up to a quarter of the circle. Therefore, their combined arc length is a quarter of the circumference of the circle.
Arc length=14×2×π×r\text{Arc length} = \frac{1}{4} \times 2 \times \pi \times r
Arc length=14×2×227×14\text{Arc length} = \frac{1}{4} \times 2 \times \frac{22}{7} \times 14
Arc length=14×2×44=22 cm\text{Arc length} = \frac{1}{4} \times 2 \times 44 = 22 \text{ cm}

2. Calculate the total length of the straight edges of the three shaded parts

Each shaded part is a sector, which has 2 straight edges, each equal to the radius (1414 cm). Since there are 3 separate shaded parts, there are 3×2=63 \times 2 = 6 straight edges in total.
Total straight edges=6×14=84 cm\text{Total straight edges} = 6 \times 14 = 84 \text{ cm}

3. Calculate the total perimeter of the three shaded parts

Total perimeter=Arc length+Total straight edges\text{Total perimeter} = \text{Arc length} + \text{Total straight edges}
Total perimeter=22+84=106 cm\text{Total perimeter} = 22 + 84 = 106 \text{ cm}

Answer

106106 cm (option 4)

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