The figure shows a cylinder which is hollow in the middle and has a thickness of 10 cm. (Taking $\pi = 3.14$.)

1. Find the outer and inner radii of the shaded face

Outer radius $R = 60 \div 2 = 30\text{ cm}$
Inner radius $r = 30 - 10 = 20\text{ cm}$

2. Calculate the area of the shaded face

$\text{Area} = \pi R^2 - \pi r^2$
$\text{Area} = 3.14 \times 30^2 - 3.14 \times 20^2$
$\text{Area} = 3.14 \times (900 - 400)$
$\text{Area} = 3.14 \times 500 = 1570\text{ cm}^2$

1. Calculate the area of the two annular bases (top and bottom faces).

Area of one annular face $= \pi R^2 - \pi r^2 = 3.14 \times (30^2 - 20^2) = 3.14 \times 500 = 1570\text{ cm}^2$
Area of two faces $= 2 \times 1570 = 3140\text{ cm}^2$

2. Calculate the outer and inner curved surface areas.

Outer curved surface area $= 2\pi R h = 2 \times 3.14 \times 30 \times 42 = 7912.8\text{ cm}^2$
Inner curved surface area $= 2\pi r h = 2 \times 3.14 \times 20 \times 42 = 5275.2\text{ cm}^2$

3. Find the total painted surface area.

Total surface area $= 3140 + 7912.8 + 5275.2 = 16328\text{ cm}^2$