Shauna takes five tests, each worth a maximum of 100 points. Her scores on the first three tests are 76, 94, and 87. In order to average 81 for all five tests, what is the lowest score she could earn on one of the other two tests?
A. 48
B. 52
C. 66
D. 70
E. 74

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Worked solution

1. 2019 AMC 8 官方解析

Shauna 参加了五场考试 . 每场最多100分 . 前三场分别得到了76 , 94 , 87分 . 如果要达到五场平均81分 , 那么剩下两场中最低的一个分数可以是多少？

Let's think if one of the two could be 0? It seems there is no possibility. Then to touch a base line, maximize the other one with 100. Let's denote the score be xx :

(76−81)+(94−81)+(87−81)+(100−81)+(x−81)=0(76 - 81) + (94 - 81) + (87 - 81) + (100 - 81) + (x - 81) = 0 ,

−5+13+6+19+(x−81)=0-5 + 13 + 6 + 19 + (x - 81) = 0 ,

x=48x = 48 .

Answer

A. 48

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