The figure below is made up of a quadrant and a circle overlapping each other. The quadrant touches the circle at points F and G.
The circle, with centre O, has a diameter of 24 cm. Find the area of the shaded parts.
(Take $\pi = 3.14$)

1. Find the area of the circle and the quadrant.

Radius of the circle, $r = 24 \div 2 = 12\text{ cm}$.
Area of the circle $= \pi r^2 = 3.14 \times 12^2 = 452.16\text{ cm}^2$.
Radius of the quadrant, $R = 24\text{ cm}$.
Area of the quadrant $= \frac{1}{4} \pi R^2 = \frac{1}{4} \times 3.14 \times 24^2 = 452.16\text{ cm}^2$.

2. Determine the area of the overlapping region.

The straight edges of the quadrant form a $90^\circ$ angle at G. Since the angle in a semicircle is $90^\circ$, these edges pass exactly through the ends of the horizontal diameter of the circle.
The overlapping region consists of the upper semicircle and the triangle formed by the horizontal diameter and point G.
Area of upper semicircle $= 452.16 \div 2 = 226.08\text{ cm}^2$.
Area of triangle $= \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 24 \times 12 = 144\text{ cm}^2$.
Total overlap area $= 226.08 + 144 = 370.08\text{ cm}^2$.

3. Calculate the total area of the shaded parts.

The shaded parts are the regions in the quadrant outside the circle, and the regions in the circle outside the quadrant.
Shaded area $= (\text{Area of quadrant} - \text{Overlap}) + (\text{Area of circle} - \text{Overlap})$
Shaded area $= (452.16 - 370.08) + (452.16 - 370.08) = 82.08 + 82.08 = 164.16\text{ cm}^2$.