A 13-cm cubical container was filled with water to a height of 11 cm.

1. Identify the dimensions of the water in the container

The container is a cube with side length $13\text{ cm}$, so the base of the water is a square of $13\text{ cm}$ by $13\text{ cm}$. The height of the water is given as $11\text{ cm}$.

2. Calculate the volume of the water

$\text{Volume} = 13 \times 13 \times 11 = 169 \times 11 = 1859\text{ cm}^3$

1. Calculate the volume of water poured from the cubical container (from part a)

Volume of water poured = $13 \times 13 \times 11 = 1859\text{ cm}^3$

2. Calculate the final volume of water in Tank Y

Final height of water in Tank Y = $\frac{5}{7} \times 28 = 20\text{ cm}$
Final volume of water in Tank Y = $25 \times 22 \times 20 = 11000\text{ cm}^3$

3. Calculate the initial volume of water in Tank Y

Initial volume of water = $11000 - 1859 = 9141\text{ cm}^3$

4. Calculate the initial height of water in Tank Y

Base area of Tank Y = $25 \times 22 = 550\text{ cm}^2$
Initial height = $9141 \div 550 = 16.62\text{ cm}$