The sketch shows the graph of y=ka−xy = ka^{-x}. The points A (−1, 6) and B (0, 3) lie on the graph. Find the value of k and of a. Answer k = ... a = ...

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Worked solution

4

1. Use point B to find $k$.

Since B(0,3)B(0,3) lies on y=ka−xy=ka^{-x},
3=ka−03=ka^{-0}
3=k×13=k\times 1
k=3k=3

2. Use point A and the value of $k$ to find $a$.

Since A(−1,6)A(-1,6) lies on the graph,
6=3a−(−1)6=3a^{-(-1)}
6=3a16=3a^1
a=2a=2

Answer

k=3k=3

a=2a=2

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