The figure below is made up of two triangles, PRS and PQT. TQ = 4 cm and the length of TQ is half the length of SR. Find the area of TQRS. Ans: ___ $\text{cm}^2$

1. Find the length of SR

$\text{SR} = 4 \times 2 = 8 \text{ cm}$

2. Find the area of triangle PRS

$\text{Height of } \triangle PRS = 9 + 9 = 18 \text{ cm}$
$\text{Area of } \triangle PRS = \frac{1}{2} \times 8 \times 18 = 72 \text{ cm}^2$

3. Find the area of triangle PQT

$\text{Area of } \triangle PQT = \frac{1}{2} \times 4 \times 9 = 18 \text{ cm}^2$

4. Find the area of TQRS by subtracting the area of triangle PQT from triangle PRS

$\text{Area of TQRS} = 72 - 18 = 54 \text{ cm}^2$