At the start of a 5-day sale, two shops A and B had 100 identical laptops each. The graphs below show the total number of laptops left unsold for each shop at the end of each day.

1. Calculate the number of laptops sold each day for Shop A and Shop B by finding the difference in unsold laptops from the previous day.

For Shop A, the number of laptops sold each day is:

• Day 1: $100 - 80 = 20$
• Day 2: $80 - 60 = 20$
• Day 3: $60 - 30 = 30$
• Day 4: $30 - 10 = 20$
• Day 5: $10 - 0 = 10$

For Shop B, the number of laptops sold each day is:

• Day 1: $100 - 90 = 10$
• Day 2: $90 - 60 = 30$
• Day 3: $60 - 40 = 20$
• Day 4: $40 - 10 = 30$
• Day 5: $10 - 0 = 10$

2. Compare the daily sales to identify the days when Shop A sold fewer laptops than Shop B.

Comparing the sales (Shop A vs Shop B):

• Day 1: $20 > 10$
• Day 2: $20 < 30$ (Shop A sold fewer)
• Day 3: $30 > 20$
• Day 4: $20 < 30$ (Shop A sold fewer)
• Day 5: $10 = 10$

Shop A sold fewer laptops on Day 2 and Day 4.

1. Determine the discounted price for each $300 block of the original price

For every $\char36{}300$ of the original price, the discount is $\char36{}50$.
Discounted price per block = $\char36{}300 - \char36{}50 = \char36{}250$.

2. Find the number of full $250 blocks in the total amount paid

Total amount paid = $\char36{}4600$.
Number of full blocks = $4600 \div 250 = 18$ with a remainder of $\char36{}100$.

3. Calculate the original price without the discount

Original price of the 18 blocks = $18 \times \char36{}300 = \char36{}5400$.
The remaining $\char36{}100$ paid did not qualify for a discount, so its original price is $\char36{}100$.
Total original price = $\char36{}5400 + \char36{}100 = \char36{}5500$.