For Questions 6 to 17, show your workings clearly in the space below each question and write your answers in the spaces provided. The number of marks available is shown in brackets [ ] at the end of each question or part-question. The total mass of three parcels was 13.8 kg. Parcel B was 1.2 kg heavier than Parcel A while Parcel C was 1.2 kg lighter than Parcel A.

  1. (a)

    How much heavier was Parcel B than Parcel C?

  2. (b)

    Find the mass of Parcel A.

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Worked solution

6(a)

1. Calculate the difference in mass between Parcel B and Parcel C

Difference=1.2+1.2=2.4 kg\text{Difference} = 1.2 + 1.2 = 2.4\text{ kg}

Answer

2.4 kg2.4\text{ kg}

6(b)

1. Express the total mass in terms of the mass of Parcel A

Let the mass of Parcel A be AA.
Mass of Parcel B = A+1.2A + 1.2
Mass of Parcel C = A−1.2A - 1.2
Total mass = A+(A+1.2)+(A−1.2)=3AA + (A + 1.2) + (A - 1.2) = 3A

2. Solve for the mass of Parcel A

3A=13.83A = 13.8
A=13.8÷3=4.6A = 13.8 \div 3 = 4.6

Answer

4.6 kg4.6\text{ kg}

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