Given $x^2-8xy+16y^2=0$ , find the value of $\dfrac{x}{y}$ . Answer ...

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Worked solution

1. Factorise the given expression as a perfect square.

$x^2-8xy+16y^2=0$
$x^2-2(x)(4y)+(4y)^2=0$
$(x-4y)^2=0$

2. Solve the resulting equation and find $\dfrac{x}{y}$.

$(x-4y)^2=0$
$x-4y=0$
$x=4y$
Dividing both sides by $y$ ,
$\frac{x}{y}=4$

Answer

$\dfrac{x}{y}=4$

AI analysis — may contain mistakes.

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